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mixer [17]
3 years ago
6

You have 0.5 L of air at a pressure of 203 kPa and -70 degrees C in a rigid, sealed container. What is the absolute temperature

of the air?
1) 70 K
2) 273 K
3) -70 K
4) 203 K
Chemistry
1 answer:
horrorfan [7]3 years ago
7 0
2) 273k is your answer. You're welcome.
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The question is incomplete, here is the complete question:

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

A gas vessel is charged with a mixture of PCl_3(g) and Cl_2(g), which is allowed to equilibriate at 450 K. At equilibrium the partial pressures of the three gases are p_{PCl_3(g)} = 0.126 atm , p_{Cl_2(g)} = 0.156 atm , and p_{PCl_5(g)} = 1.60 atm. What is the value of K_p at this temperature?

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<u>Explanation:</u>

For the given chemical equation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{PCl_5}}{p_{Cl_2}\times p_{PCl_3}}

We are given:

p_{PCl_5}=1.60atm\\p_{PCl_3}=0.126atm\\p_{Cl_2}=0.156atm

Putting values in above equation, we get:

K_p=\frac{1.60}{0.156\times 0.126}\\\\K_p=81.4

Hence, the K_p for the given reaction is 81.4

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