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mixer [17]
3 years ago
6

You have 0.5 L of air at a pressure of 203 kPa and -70 degrees C in a rigid, sealed container. What is the absolute temperature

of the air?
1) 70 K
2) 273 K
3) -70 K
4) 203 K
Chemistry
1 answer:
horrorfan [7]3 years ago
7 0
2) 273k is your answer. You're welcome.
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jolli1 [7]

Answer:

0.83 g

Explanation:

Step 1: Write the balanced equation

Fe + CuSO₄ ⇒ Cu + FeSO₄

Step 2: Calculate the moles corresponding to 0.75 g of Fe

The molar mass of Fe is 55.85 g/mol.

0.75g \times \frac{1mol}{55.85g} = 0.013 mol

Step 3: Calculate the moles of Cu produced from 0.013 moles of Fe

The molar ratio of Fe to Cu is 1:1. The moles of Cu produced are 1/1 × 0.013 mol = 0.013 mol.

Step 4: Calculate the mass corresponding to 0.013 moles of Cu

The molar mass of Cu is 63.55 g/mol.

0.013mol \times \frac{63.55g}{mol} = 0.83 g

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