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2 years ago

What is the name of this hydrocarbon?

Chemistry

2 answers:

jenyasd209 [6]2 years ago

5 0

Answer:

2-methylebutane

Explanation:

it is a hydrocarbon and there is a specific Rule for its nomenclature.

that is known as IUPAC naming system. According to it

The compound that has all single bonds name ends on ane.
Names according to the number of Carbons,

* For one carbon compound it is known as methane,

* For 2 ethane,

* For 3 propane

* For 4 Butane and so on.

select the longest chain of compound
Start numbering with lowest substituted position at carbon
branch compound name as Iso and neo as whole

So keeping in mind the compound can be named as

2-methylebutane

As the longest chain contain four carbon atoms so it will name as butane
The substitution of methyl group is on C-2

*Note: it can also named as isopantane as it is branched and have five carbons but it could not be 3-isopentane.

Natalka [10]2 years ago

5 0

Answer:

B. 2-methylebutane

Explanation:

Edge 2020

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valentinak56 [21]

Answer: The number of grams of $H_2$ in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L (1L=1000ml)

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K$

$n=\frac{PV}{RT}$

$n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles$

Mass of hydrogen = $moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g$

The number of grams of $H_2$ in 1620 mL is 1.44 g

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3 years ago

Ionic or covalent C2H5OH

Afina-wow [57]

Answer:

Covalent

Explanation:

A molecule of C₂H₅OH has C-C, C-H, C-O, and O-H bonds.

A bond between A and B will be ionic if the difference between their electronegativities (ΔEN) is greater than 1.6.

$\begin{array}{ccc}\textbf{Bond} & \textbf{$\Delta$EN} & \textbf{Polarity}\\\text{C-C} & 2.55 - 2.55 = 0.00 & \text{Nonpolar covalent}\\\text{C-H} & 2.55 - 2.20 = 0.35 & \text{Nonpolar covalent}\\\text{C-O} & 3.44 - 2.55 = 0.89 & \text{Polar covalent}\\\text{O-H} & 3.44 - 2.20 = 1.24 & \text{Polar covalent}\\\end{array}$