This is the unique answer
What is the name of this hydrocarbon?
2 answers:
Answer:
2-methylebutane
Explanation:
it is a hydrocarbon and there is a specific Rule for its nomenclature.
that is known as IUPAC naming system. According to it
- The compound that has all single bonds name ends on ane.
- Names according to the number of Carbons,
* For one carbon compound it is known as methane,
* For 2 ethane,
* For 3 propane
* For 4 Butane and so on.
- select the longest chain of compound
- Start numbering with lowest substituted position at carbon
- branch compound name as Iso and neo as whole
So keeping in mind the compound can be named as
2-methylebutane
- As the longest chain contain four carbon atoms so it will name as butane
- The substitution of methyl group is on C-2
*Note: it can also named as isopantane as it is branched and have five carbons but it could not be 3-isopentane.
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Answer:
Explanation:
The formula for the heat released is
q = mCΔT
Data:
m = 395 g
C = 4.184 J·°C⁻¹g⁻¹
ΔT = 55 °C
Calculations:
q = 395 × 4.184 × 55 = 91 000 J = 91 kJ
The water will absorb of energy.
Answer:
(a) AL
(b) Sc
(c)Al
Explanation:
Ionization Energy is the energy required to remove electrons from the outer most orbitals of atom.
The higher the electron is on energy level the farther its from nucleus and more loosely bonded thus need lesser energy.
By looking at electron configuration we can figure out which electron will need more energy.
<h3>(a)Na, Mg, Al</h3>1s², 2s², 2p⁶, 3s², 3p⁶,4s², 3d¹
Na₁₁ ⇒ 1s², 2s², 2p⁶, 3s¹
Mg₁₂ ⇒ 1s², 2s², 2p⁶, 3s²
Al₁₃ ⇒ 1s², 2s², 2p⁶, 3s², 2p¹
Al will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.
<h3>(b) K, Ca, Sc</h3>K₁₉⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s²
Ca₂₀⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s²
Sc₂₁⇒1s², 2s², 2p⁶, 3s², 3p⁶,4s², 3d¹
Sc will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.
<h3>(c) Li, Al, B</h3>Li₃ ⇒ 1s², 2s¹
Al₁₃ ⇒ 1s², 2s², 2p⁶, 3s², 2p¹
B₅ ⇒ 1s², 2s², 2p¹
Al will have lowest IE₃ as its third electron will be in highest energy level and more loosely bonded to nucleus.
