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Zarrin [17]
3 years ago
8

What is the name of this hydrocarbon?

Chemistry
2 answers:
jenyasd209 [6]3 years ago
5 0

Answer:

2-methylebutane

Explanation:

it is a hydrocarbon and there is a specific Rule for its nomenclature.

that is known as IUPAC naming system. According to it

  • The compound that has all single bonds name ends on ane.
  • Names according to the number of Carbons,

                * For one carbon compound it is known as methane,

                * For 2 ethane,

                * For 3 propane

                * For 4 Butane and so on.

  • select the longest chain of compound
  • Start numbering with lowest substituted position at carbon
  • branch compound name as Iso and neo as whole

So keeping in mind the compound can be named as

2-methylebutane

  • As the longest chain contain four carbon atoms so it will name as butane
  • The substitution of methyl group is on C-2

*Note: it can also named as isopantane as it is branched and have five carbons but it could not be 3-isopentane.

Natalka [10]3 years ago
5 0

Answer:

B. 2-methylebutane

Explanation:

Edge 2020

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Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

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                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

                        = 1.44 \times 10^{-3}s^{-1}&#10;

Initial fat concentration S_{o} = 45 mol/m^{3}

                                                = 45 mmol/L

Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

                                      = 45 (1 - 0.80)

                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

                    t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]

Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s&#10;}{K_{M} ln (\frac{45 mmol/L&#10;}{9 mmol/L&#10;}) + (45 mmol/L - 9 mmol/L&#10;)]

              = 1642.83 s \times \frac{1 min}{60 sec}

              = 27.38 min

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Which set of numbers gives the correct possible values of I for n = 22
Alexandra [31]

Answer:

Hello friends

Explanation:

<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>

<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>

<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>

<h3>Hope it's helpfully. </h3>
4 0
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What element is in group 17 and period 3 of the periodic table?
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Answer:

Chlorine is the element located in period 3, group 17 of the periodic table.

Explanation:

6 0
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