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mestny [16]
4 years ago
12

How many milligrams are in 12 lbs? (show using dimensional analysis)

Mathematics
1 answer:
mamaluj [8]4 years ago
7 0
5443108.44 millagram
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Solve p^2+6p+8 by using square roots<br> Thank You!
weqwewe [10]
P^3+square root 19
Alternative form=7.3589
6 0
3 years ago
Mrs. Khan is mailing 2 packages. The large package weighs 6 2 3 pounds. The small package weighs 3 1 2 pounds. Which statement B
vagabundo [1.1K]

<u>Answer:</u>

Mrs. Khan is mailing 2 packages. Subtract 623 – 312 best describe how to find out how much heavier the larger package is. Hence Option C is correct

<u>Solution:</u>

Given that  

Mrs khan is mailing two packages.

Weight of larger package = 623 pounds  

Weight of small package = 312 pounds

Now we need to find how much heavier larger package compare to smaller one is.

To get this if we remove weight of smaller package from larger package , we will get how much larger package is heavier.

That is<em> Weight of larger package – Weight of smaller package</em> = 623 pounds – 312 pounds

Hence option C) subtract 623 – 312 best describe how to find out how much heavier the larger package is.

6 0
3 years ago
Read 2 more answers
Is 0.008 or 0.02 greater
topjm [15]
0.02 is greater because it has a two in the hundredths place while 0.008 only has a 0.
5 0
4 years ago
Read 2 more answers
Three people of kaui Island are named Alice, Bob and Carol. At least one of them is a Knight and at least one is a Knave. Exactl
IrinaVladis [17]

Answer:  Alice has the prize

<u>Step-by-step explanation:</u>

\boxed{\begin{array}{c|c|c||l}\underline{Alice}&\underline{Bob}&\underline{Carol}&\underline{Prize}\\T&T&F&\text{Alice}\\T&F&F&\text{no possible answer}\\T&F&T&\text{no possible answer}\\F&T&T&\text{no possible answer}\\F&F&T&\text{no possible answer}\\F&T&F&\text{no possible answer}\end{array}}

Line 1:

Alice: Bob doesn’t have the prize (T) ... either Alice or Carol

Bob: I don’t have the prize (T) ... either Alice or Carol

Carol: I have the prize (F) ... either Alice or Bob

          Alice is true for all of them!

Line 2:

Alice: Bob doesn’t have the prize (T) ... either Alice or Carol

Bob: I don’t have the prize (F) ... Bob

Carol: I have the prize (F) ... either Alice or Bob

            <em>nobody satisfies all three statements.</em>

Line 3:

Alice: Bob doesn’t have the prize (T) ... either Alice or Carol

Bob: I don’t have the prize (F) ... Bob

Carol: I have the prize (T) ... Carol

            <em>nobody satisfies all three statements.</em>

Line 4:

Alice: Bob doesn’t have the prize (F) ... Bob

Bob: I don’t have the prize (T) ... either Alice or Carol

Carol: I have the prize (T) ... Carol

            <em>nobody satisfies all three statements.</em>

<em />

Line 5:

Alice: Bob doesn’t have the prize (F) ... Bob

Bob: I don’t have the prize (F) ... Bob

Carol: I have the prize (T) ... Carol

            <em>nobody satisfies all three statements.</em>

<em />

Line 6:

Alice: Bob doesn’t have the prize (F) ... Bob

Bob: I don’t have the prize (T) ... either Alice or Carol

Carol: I have the prize (F) ... either Alice or Bob

            <em>nobody satisfies all three statements.</em>

3 0
3 years ago
22.
Vlada [557]

Step-by-step explanation:

\sqrt{p}  =  \sqrt[r]{w -  {as}^{2} }

Find raise each side of the expression to the power of r

That's

<h2>( \sqrt{p} )^{r}  =  (\sqrt[r]{w -  {as}^{2} } ) ^{r}</h2>

we have

<h2>( \sqrt{p} )^{r}  =  w -  {as}^{2}</h2>

Send w to the left of the equation

<h2>( \sqrt{p} )^{r}  - w =  -{as}^{2}</h2>

Divide both sides by - a

We have

<h2>{s}^{2}  =  -\frac{( \sqrt{p} )^{r}  - w}{a}</h2>

Find the square root of both sides

We have the final answer as

<h2>s =  \sqrt{ -\frac{( \sqrt{p} )^{r} - w }{a} } </h2>

Hope this helps you

3 0
3 years ago
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