Question

From his eye, which stands 1.59 meters above the ground, Francisco measures the

Answer 1

The height of the skyscraper to the nearest tenth is 234. 95 meters.

How to determine the height

From the information given, we have:

• angle of elevation = 32°
• length of the base, adjacent side = 376 meters
• height of the skyscraper, opposite side = x meters

To determine the height of the elevator, let's use the tangent identity

We have that;

tan θ = opposite/ adjacent

The value of the opposite side is 'x' which is the height of the skyscraper and the value of the adjacent side is 376 meters which is the length of the base of the skyscraper

Now, substitute the values, we have;

tan 32 = x/ 376

cross multiply

x = tan 32 × 376

x = 0. 6249 × 376

x = 234. 95 meters

We know that the 'x' represents the opposite side and thus the height of the skyscraper

Thus, the height of the skyscraper to the nearest tenth is 234. 95 meters.

Learn more about angle of elevation here:

brainly.com/question/19594654

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