M(month)*g(amount of games)=x(how many games sold in a month)
Answer: The required length of the segment AA' is 11 units.
Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.
We are to find the length of the segment AA'.
We know that
if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).
So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).
Now, we have the following distance formula :
The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

Therefore, the length of the segment AA' is given by

Thus, the required length of the segment AA' is 11 units.
Suppose there are 19x students, 1x teachers
19x+1x=400
20x=400
x=20
there are 20 teachers and 380 students.
Answer:
Step-by-step explanation:
Hello,
we assume that a is different from 0 otherwise there is not much we can say on c and then we can write
a(c+b)=d
<=> ac+ab=d
<=> ac = d - ab
<=> 
Hope this helps