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soldi70 [24.7K]
3 years ago
9

Which function has a greater y-intercept?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0

Answer:

Option C, both functions have an y-intersect equal to 2.

Step-by-step explanation:

When we have a function f(x), the y-intercept is the value f(0). This is the point where the graph of the function intersects the y-axis.

Then, for f(x) = -x^2 + 5*x + 2

The y-intercept is:

f(0) = -0^2 + 5*0 + 2 = 2

f(0) = 2

And for g(x) we do not have the equation, but we have the graph, so we can just look at which value of y does the graph intersects the y-axis.

We can see that the graph intersects the graph at y = 2

Then the y-intersect is: g(0) = 2

So both functions have the same y-intersect. Then the correct option is C.

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A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form
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Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity v_o of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

h = -16t^2 +v_ot + 8

Thus;

Replacing the value of v_o =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

0= -16t^2 +(1120)t + 8

=  -16t^2 +(1120)t + (8-0)

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}, we have:

= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}

= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}

= \dfrac{140 \pm \sqrt{19608}}{4}

= \dfrac{140 \pm 140}{4}

=\dfrac{140+ 140}{4} \ \ \ OR \ \ \  \dfrac{140-140}{4}

=\dfrac{280}{4} \ \ \ OR \ \ \  0

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

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3 years ago
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