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Ganezh [65]
2 years ago
8

I need help on this question please help me

Mathematics
1 answer:
Anastasy [175]2 years ago
6 0

Answer:

Step-by-step explanation:

6*[4-(42-63)]=

6*[4-(-21)]=

6*[4+21]=

6*25=150.

6*[4-9÷3]=

6*[4-27]=

6*(-23)=-138.

6*[4-3]=

6*1=6.

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goldfiish [28.3K]

Answer:

47 cm im nnot sure

Step-by-step explanation:

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3 years ago
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irga5000 [103]

Answer:

Use compatible numbers that are close to the actual numbers

Choose 36 for 35 3/4 and 6 for 5 7/8 because the divide evenly.

Step-by-step explanation:

Compatible numbers are numbers that are close to the actual values of a particular number. They make estimating easier when yo udo the different operations.

We choose 36 for 35 3/4 because 36 is closer to its value that 34. Conveniently, 5 7/8 is closer to 6 than 5, and they divide evenly. So a best estimate for the number of rows Holly can make would be:

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3 years ago
What are the dimensions for this triangle?
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Answer:

2 and 2

Step-by-step explanation:

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Area of triangular prism
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In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
3 years ago
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