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melamori03 [73]
4 years ago
9

Determine whether each equation defines y as function of x, 2x+y=8​

Mathematics
1 answer:
solong [7]4 years ago
6 0

Answer:

Yes. This equation defines y as function of x.

Step-by-step explanation:

Step 1:

Solve the equation for y (this puts the equations in terms of y)

2x+y=8​     becomes

 y = 2x - 8    

This is a linear equation, which is a funtion.  


*Another way to solve this is to look at the graph.  Graphing this equation gives us a line.  Use the vertical line test to see if it's a function.  

To pass the vertical line test (VLT), there can only be one y value to each x value along the graph.  If it passes the VLT, the equation is a function.

If it fails the VRT, the equation is not a function.

You might be interested in
Slope and the intercept
Pie

Answer:

y-intercept: (0, 3) slope: 3

Step-by-step explanation:

7 0
3 years ago
Help me plz quick my phone about to die
konstantin123 [22]
I'll do the first graph.

We can easily find the y intercept by inputting 0 for x.

y = -2(0) + 7
y = 7

The y-intercept is (0, 7)

To find the x intercept, isolate x.

y = -2x + 7
Add 2x to both sides.
2x + y = 7
Subtract y from both sides.
2x = -y + 7
Divide by 2 on both sides.
x = -1/2y + 3.5

Input 0 for y.

x = -1/2(0) + 3.5
x = 3.5

The x intercept is (3.5, 0)

Now try the rest own your own! :)
5 0
4 years ago
Can someone please explain - Thanks!
Reil [10]
They're not congruent.

If you count the numbers between AC and BE, they're different.

AC - goes from -7 to 0, which is 7 spaces
BE - goes from -2 to 6, which is 8 spaces

4 0
4 years ago
Read 2 more answers
I need help please ..
Vinvika [58]

Answer:

660.5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)
PIT_PIT [208]

9514 1404 393

Answer:

  • common denominator: (x² -4)
  • simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

  a² -b² = (a -b)(a +b)

__

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

  \dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}

3 0
3 years ago
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