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FromTheMoon [43]
2 years ago
13

Please help I need an answer

Mathematics
1 answer:
kkurt [141]2 years ago
7 0

The midpoint of the given line in coordinate form (x, y) is -0.5, 0)

<h3>Midpoint of a line</h3>

The midpoint of a line is the middle of the given line. Given the coordinate points (x1, y1) and (x2, y2), the midpoint of the line is given as:

M(x, y) = {x1+x2/2, y1+y2/2}

Given the coordinate points on the line (-2, 1) and (1, -1)

Substitute the given coordinate points into the formula to have:

M(x, y) = {-2+ 1/2, 1-1/2}

M(x, y) = {-1/2, 0/2}
M(x, y) =(-0.5, 0)

Hence the midpoint of the given line in coordinate form (x, y) is (-0.5, 0)

Learn more on midpoint here: brainly.com/question/5566419

#SPJ1

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How do i find the shorted distance between the point and the line
m_a_m_a [10]

Answer:

5 units

Step-by-step explanation:

3x + 4y = 8

4y = -3x+8

y = -3/4+2

The shortest distance between a point and a line is the perpendicular line.

Slope of the perpendicular line: 4/3 and point (-3,-2)

b = -2-(4/3)(-3) = 2

Equation of the perpendicular line: y=4/3x+2

y is equal y

4/3x+2= -3/4x+2

4/3x +3/4x = 2-2

x = 0

Plug x=0 into one of the equations to find y

y = 4/3(0) + 2

y = 2

(0,2) and (-3,-2)

Distance = sqrt [(-3-0)^2 + (-2-2)^2]

Sqrt (-3)^2+ (-4)^2

Sqrt 25 = 5

3 0
3 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
How many feet are traveled by a person riding once around the merry -go-round ? Clare says, " The radius of the merry -go-round
Naya [18.7K]
If this is a question about who is correct Clair is correct
6 0
3 years ago
An altitude of a right triangle to its hypotenuse divides this hypotenuse into two segments that measure 9cm, and 16cm. What are
ozzi

Answer:

Step-by-step explanation:

Let a be the length of the altitude, then from the given triangles, applying the basic proportionality theorem,  we get

\frac{BD}{AD}=\frac{DC}{BD}

⇒(BD)^{2}=DC{\times}AD

⇒(BD)^2=9{\times}16

⇒BD=\sqrt{144}

⇒BD=12 cm

Thus, the length of altitude is: 12 cm.

Now, \frac{AB}{AD}=\frac{AC}{AB}

⇒(AB)^{2}=220

⇒AB= 14.83 cm

Also, \frac{BC}{DC}\frac{AC}{BC}

⇒(BC)^{2}=400

⇒BC=20 cm

Thus, the lengths of the legs of this triangle are 14.83 and 20 cm.

6 0
3 years ago
Read 2 more answers
The mass of Earth is approximately 5.9 x 1024 kg, and the mass of Venus is approximately 4.9 x 1024 kg. . Find their combined ma
xxMikexx [17]

Answer: 5659.2

Step-by-step explanation:

multiply separately first

  • 5.9 * 1024= 6041.6

4.9 *1024 =5017.6

  •       then add the products

6041.6+5017.6=5659.2

8 0
3 years ago
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