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3 years ago

What is the answer to 1-5

Mathematics

1 answer:

34kurt3 years ago

5 0

1. EFG

2. F

3. FA and FB Take a moment to look at this one. The two rays are pointing in opposite directions. They are 180o apart. They share a common point at F.

FE and FG does the same thing.

4. No G is on a line that has only one point on the plane and that point is F.

5, AC has an infinite number of points on the plane.

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The sutton police department must write, on average, 6 tickets a day to keep department revenues at budgeted levels. suppose the

lakkis [162]

The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
$P(k \, events) = e^{-\lambda } ( \frac{\lambda ^{k}}{k!} )$

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
$P(k \, tickets/day)=e^{-6.5} ( \frac{6.5 ^{k}}{k!} )$
The distribution is graphed as shown below.

Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.

8 0

3 years ago

If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac

mezya [45]

There are $\binom{52}4$ ways of drawing a 4-card hand, where

$\dbinom nk = \dfrac{n!}{k!(n-k)!}$

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are $\binom{13}4$ ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are $\binom41$ ways of picking a card of any given value. We draw 4 cards from the deck, so there are $\binom41^4$ possible hands in which each card has a different value.

Then there are $\binom{13}4 \binom41^4$ total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

$\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761$

4 0

2 years ago

How many times larger is 9 x 10^9 than 3 x 10^-4?

andrezito [222]

The larger value is 9 x 10^9
The smaller value is 3 x 10^(-4)

Divide the larger over the smaller
Doing so will have you divide the coefficients 9 and 3 (numbers in front of the "times ten to the..." portions) to get 9/3 = 3.
Then you'll also subtract the exponents: 9 minus (-4) = 9 - (-4) = 9 + 4 = 13

In summary so far, we got a coefficient of 3 and an exponent of 13

So the final answer is 3 x 10^13 (assuming you want scientific notation)

If you want to convert to standard notation, instead of scientific notation, move the decimal point in 3.0 thirteen spots to the right to get

30,000,000,000,000

there are 13 zeros (four groups of 3 plus one just after the 3) in that value above. This is the number 30 trillion

8 0

3 years ago

(02.0

Anestetic [448]

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Step-by-step explanation:hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhjjjjjjjjjjjjjjjjjjjjjjhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

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3 years ago

Graph 2x-5y=1 <br> Help I don’t know how to do it

lapo4ka [179]

Answer:

Step-by-step explana

Move all terms that don't contain

to the right side and solve.

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2 years ago