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Alborosie
3 years ago
5

Solve the system of linear equations by graphing. Round the solution to the nearest tenth.

Mathematics
2 answers:
Soloha48 [4]3 years ago
9 0

Answer: The correct answer is (1.2, 4.4).

hope this is helpful (:

jeyben [28]3 years ago
6 0

Answer:

The approximate solution to the system is (1.2, 4.4)

x = 1.2 and y = 4.4

Step-by-step explanation:

The solution of the system of linear equations equation y = –0.25x + 4.7 and y = 4.9x – 1.64 is shown in the attached graph. The red line represents the equation y = –0.25x + 4.7 and the blue line represents the equation  = 4.9x – 1.64.

The solution of the system of equations is their point of intersection shown on the graph.

The point of intersection is (1.231, 4.392). To the nearest tenth, it is (1.2, 4,4). So x = 1.2 and y = 4.4.

So the approximate solution to the system is (1.2, 4.4)

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We're suppose to measure the trigonometric values of the triangles and the values of indicates angles .For that,We need to know that,Sin θ = side opposite to angle  θ / HypotenuseCos θ = side adjacent to angle θ / HypotenuseTan  θ = side opposite to angle θ/side adjacent to angle θNow,In the first triangle,We're provided by,side opposite to angle  θ =QR =24side adjacent to angle θ = PR = 10Hypotenuse = PQ = 26So,Sin P = 24/26Cos P = 10/26Tan P = 24/10m∠P  = sin p° = 24/26m∠P= sin^-1(24/26)m∠P= 67.38 °In the second triangle,We're provided by,side opposite to angle  θ =MO =9side adjacent to angle θ = NO = 40Hypotenuse = MN= 41So,Sin N= 9/41Cos N= 40/41Tan N= 9/40m∠N  = sin N° = 9/41m∠N= sin^-1(9/41)m∠N= 12.68°In the third triangle,We're provided by,side opposite to angle  θ =AC =15side adjacent to angle θ = AB = 8Hypotenuse = BC = 17So,Sin B = 15/17Cos B = 8/17Tan B = 15/8m∠B  = sin p° = 15/17m∠B= sin^-1(15/17)m∠B= 61.93°In the fourth triangle,We're provided by,side opposite to angle  θ =BC =8side adjacent to angle θ = AC = 6Hypotenuse = AB = 10So,Sin A = 8/10Cos A = 6/10Tan A = 8/6m∠A  = sin p° = 8/10m∠A= sin^-1(8/10)m∠P= 53. °*53.13°

Step-by-step explanation:

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