When you have an irregular figure, you can divide it so that it becomes multiple normal figures. You already did this in the picture, now you just have to find the area of each shape and then add them all together.
From bottom to top:
A=1/2 (b1+b2)h
A= 1/2 (4+2.24)(2)
A= 6.24
(you have two of these on either side)
A=bh
A=6(4)
A=24
A=1/2 bh
A= 1/2 (4)(4)
A=8
(NOTE: there is an error in your drawing. The height of the triangle cant be determined because the 10 value spans over the entire figure when the wings of the rocket are 4 units long and then the body is 6 units long, making it equal 10 already. I'm assuming that the 10 is supposed to go from the bottom of the rectangle to the top of the triangle)
Total figure= 6.24 + 6.24 + 24 + 8
total figure = 44.48
The answer would be
x = 160/147
or
x = 1 and 13/147
Answer:
B
Step-by-step explanation:
If Sean wants to but both the muffin and cookie then this addition. 3 +m shows the correct expression. the answer is b
The area of a circle is A=πr².
Since π is about 3.14 we can substitute that into the equation.
So A=3.14×r²
We can substitute the given radius for r.
A= 3.14 × 5²
When a number is squared, or has the two over it, we multiply it by itself.
5 × 5= 25
A= 3.14 × 25
Simplify this and the area of the circle is about 78.5
A≈78.5
