Use the identity cos^2 (a/2) = 1/2 (1 + cos a) so
cos^ 2 22.5 = cos^2 (45/2) = 1/2 ( 1 + cos 45) = 1/2(1 + sqrt2/ 2)4 = 1/2 + sqrt2/4
cos 22.5 = sqrt ( 1/2 + sqrt2/4) Answer
The range of f(x) = 6x – 2 is [16,46]
According to the statement
we have given the function f(x) = 6x – 2 and the given interval is 3 < x ≤ 8
we know that to find the range of function we have to fill the values in it and then find the range of this function.
So, range is basically a difference between the lowest and the highest value.
Here the given function is f(x) = 6x – 2
when f(3) then
f(3) = 18-2
f(3) = 16.
and when f(8) then
f(8) = 48-2
f(8) = 46.
after put the values we seen that the range of this function is 16,46.
So, The range of f(x) = 6x – 2 is [16,46]
Learn more about RANGE here brainly.com/question/24326172
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Answer:
A=(n * s * a) 2A=(n*s*a)2
Step-by-step explanation:
A=(n * s * a) 2A=(n*s*a)2 where n is the number of sides, s is the length of one side and a is the apothem
Answer:
r= 3b
Step-by-step explanation:
We can find the slope of the line by using
m= (y2-y1) /(x2-x1)
= (12-9)/ (4-3)
= 3/1
The slope is 3
We can use the point slope form for the equation of a line
y-y1 = m(x-x1)
y-12 = 3(x-4)
Distribute the 3
y-12 = 3x-12
Add 12 to each side
y -12+12 = 3x-12+12
y= 3x
let r =y
and x=b
r = 3b
Separate the inequalities by part.
We'll do 8 < 12+c first then 12+c<12 next.
Then 12+c<12
Then mix c<0 and c>-4 as we'll get 
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