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zhenek [66]
1 year ago
12

Akira and her puppy are both dressing up as superheroes for Halloween this year. Akira needs 1 yard of cloth for her cape. She a

lso needs 1 foot of cloth for her puppy's cape. How many feet of cloth should she buy for their capes?
Mathematics
1 answer:
Ahat [919]1 year ago
8 0

The feet of cloth that she should buy for the capes is 4 feet.

<h3>How many feet should she buy?</h3>

The mathematical operations that would be used to determine the answer are addition and multiplication.

Addition is the process of summing two or more numbers together. Multiplication is the process of determining the product of two or more numbers.

The first step is to convert yard to feet

According to the unit of conversion : 1 yard = 3 feet

1 x 3 = 3 feet

The second step is to add the feet needed for Akira's cape with the foot needed for the puppy's cape

Total feet needed = 3 + 1 = 4 feet

To learn more about addition, please check: brainly.com/question/349488

#SPJ1

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550000000000000000 • 0.00000000044
nasty-shy [4]

Answer:

550000000000000000 0.00000000044

Step-by-step explanation:

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5 0
2 years ago
1. Two triangles have the following congruence statement: ACGI = AMPR Name all 6 pairs of corresponding congruent parts. 1.​
rodikova [14]

Answer:

\angle C \cong \angle M

\angle G \cong \angle P

\angle I \cong \angle R

\overline{CG} \cong \overline{MP}

\overline{GI} \cong \overline{PR}

\overline{CI} \cong \overline{MR}

Step-by-step explanation:

Given the congruence statement ∆CGI \cong ∆MPR, it follows that the corresponding sides of both ∆s are equal, as well as the corresponding vertices or angles. It implies that ∆CGI and ∆MPR are of the same shape and size.

✅Thus, the 6 pairs of the corresponding congruent parts of ∆CGI and ∆MPR are:

\angle C \cong \angle M

\angle G \cong \angle P

\angle I \cong \angle R

\overline{CG} \cong \overline{MP}

\overline{GI} \cong \overline{PR}

\overline{CI} \cong \overline{MR}

3 0
3 years ago
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
Kelly's new snowboard is 120% longer than her old snowboard. If the new snowboard is 150 cm, how long is her old snowboard?
BabaBlast [244]
12.5 is the correct answer
6 0
3 years ago
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