Write an equation of the line that is perpendicular to -x+y=15 and passes through the point (2,-5)
1 answer:
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Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:
- Segment bisector of XY = line n
- Length of XY = 6
<em><u>Recall:</u></em>
- A line that divides a segment into two equal parts is referred to as segment bisector.
In the diagram attached below, line n divides XY into XM and MY.
Thus, the segment bisector of XY is: line n.
<em><u>Find the value of x:</u></em>
XM = MY (congruent segments)
- Substitute
- Collect like terms and solve for x
XY = XM + MY
- Plug in the value of x
Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:
- Segment bisector of XY = line n
- Length of XY = 6
Learn more here:
Use the quadratic equation to solve this (image of the quadratic equation is below)
Remember that quadratic functions are set up like so:
To make the equation 3x² + 4x = -8 into a quadratic function you must bring -8 to the left side of the equation so it equals zero. To do this add 8 to both sides
3x² + 4x + 8= -8 + 8
3x² + 4x + 8 = 0
That means that in this equation...
a = 3
b = 4
c = 8
^^^Plug these numbers into the quadratic equation and solve (Keep in mind that +/- is ± )
^^^There is no real solution to this equation. You must have an imaginary solution
Simplify
Hope this helped!
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