Complete question:
The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
Answer:
After 210 s the concentration of SO2Cl2 will be 0.121 M
Explanation:
![ln\frac{[A_t]}{[A_0]} =-kt](https://tex.z-dn.net/?f=ln%5Cfrac%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%20%3D-kt)
where;
At is the concentration of A at a time t
A₀ is the initial concentration of A
k is rate constant = 1.44×10⁻⁴ s⁻¹
t is time
ln(At/A₀) = -( 1.44×10⁻⁴)t
ln(At/0.125) = -( 1.44×10⁻⁴)210
ln(At/0.125) = -0.03024
At/0.125 = 0.9702
At = 0.125*0.9702
At = 0.121 M
Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M
In the given reaction fluorine is reduced and chlorine is oxidized.
<h3>What is oxidation and reduction?</h3>
Oxidation is a process in which addition of oxygen or removal of hydrogen and electron takes place, while reduction is a process in which addition of hydrogen & electrons or removal of oxygen takes place.
Given chemical reaction is:
F₂ + 2HCl → Cl₂ + 2HF
- In the above reaction fluorine is reduced as it accepts an electron and increase in it its oxidation state takes from 0 to -1, which shows reduction.
- In the reaction chlorine is oxidized as it losses an electron and decrease in its oxidation state takes from -1 to 0, which shows oxidation.
- Oxidation half reaction is:
F₂ + 2e⁻ → 2F⁻
- Reduction half reaction is:
2Cl⁻ → Cl₂ + 2e⁻
Hence, fluorine is reduced and chlorine is oxidized in the given reaction.
To know more about oxidation & reduction, visit the below link:
brainly.com/question/4222605
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