Question

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer 1

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2  will be 0.121 M

Explanation:

$ln\frac{[A_t]}{[A_0]} =-kt$

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) =  -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

$\frac{A_t}{0.125} = e^{-0.03024$

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2  will be 0.121 M