Question

The periodic time, t, of a pendulum varies directly as the square root of its length, l. t = 6 when l = 9. find t when l = 25.

Answer 1

The periodic time, t, of a pendulum range directly as the square root of its length, l. t = 6 when l = 9. If l = 25 then the periodic time, T exists at 10.

What is periodic time?

The period, or periodic time, of a periodic variation of a quantity, exists described as the time interval between two consecutive repetitions.

Given: The periodic time, t, of a pendulum goes directly as the square root of its length, l if t = 6 when l = 9.

If $T \alpha\ l^2$ then $T^2$ α $\sqrt{l}$

$T^2 = l$

Let, $T^2 = kl,$ where k exists constant

t = 6 when l = 9.

So, $6^2 = k*9$

$k = 6^2/9 = 4$

$T^2 = 4*l$

If l = 25

$T^2 = 4 * 25 = 100$

$T = \sqrt{100}$

T = 10

Therefore, the periodic time, T exists 10.

To learn more about a simple pendulum refer to:

brainly.com/question/14641927

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