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Serggg [28]
2 years ago
11

n="absmiddle" class="latex-formula">
Mathematics
2 answers:
Mandarinka [93]2 years ago
8 0

Answer:

The answer to this question is a = 9.

Step-by-step explanation:

To solve this problem, we need isolate the variable "a" on one side of the equation. Our first step must be to remove the square root. To do this, we should perform the inverse operation, which is squaring both sides.

√2a - 14 = 2

(√(2a - 14))² = 2²

2a - 14 = 4

Next, we should add 14 to both sides of the equation to get the variable term by itself.

2a - 14 + 14 = 4 + 14

2a = 18

Finally, we should divide both sides of the equation by 2 to remove the coefficient from the variable term.

a = 9

Therefore, the correct answer is a = 9.

Here are some additional resources for solving equations with square roots:

brainly.com/question/14956063

brainly.com/question/1365584

azamat2 years ago
6 0

Answer:

a = 9

Step-by-step explanation:

\sqrt{2a-14} = 2

2a - 14 = 4

2a = 18

a = 9

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w = 1.2 or 6/5

Step-by-step explanation:

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2 years ago
How do you simplify√18 ?
igomit [66]

Answer:

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8 0
3 years ago
i need 8 and 9 to be done if this isnt cropped correctly, giving a pretty good amount of points for it
Akimi4 [234]

Answer:

question number 8 has a <u>positive slope</u> is the the answer for number 8 and the rate for number 8 is that counts by 2's on the X axis and on the Y axis it counts by 10's

and question number 9 has a <u>negative slope</u> is the answer for number 9 and the rate of the graph for number 9 is that it decreases by 3's on the X axis and on the Y axis it goes up by 6's

Step-by-step explanation:

8 0
3 years ago
What is the sum of the infinite geometric series?<br><br> 120 + 20+ 10/3 + 5/9+...
Sergeu [11.5K]

Answer:

for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

Step-by-step explanation:

i) from the given series we can see that the first term is a_{1 } = 120.

ii) let the common ratio be r.

iii) the second term is 20 = 120 × r

   therefore r = 20 ÷ 120 = \dfrac{1}{6}

iv) the third term is \frac{10}{3} = 20 × r

    therefore r = \dfrac{10}{3} ÷ 20 = \dfrac{1}{6}

v) for an infinite geometric series the formula for the sum of the infinite geometric series when the common ratio is less than one is given by

\frac{a_{1} }{1 - r} = \frac{120}{1 - \frac{1}{6} } = \frac{120}{\frac{5}{6} } = \frac{120 \times 6}{5} = 144.

6 0
2 years ago
PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION
yaroslaw [1]

Answer:

-2/3= x

Step-by-step explanation:

<u><em>square all the terms on both sides to get rid of the radicals:</em></u>

1^{2} + (\sqrt{1-x} )^{2} = (\sqrt{2x+4}) ^{2}

<u><em>exponent 2 and the radical cancel each other:</em></u>

1 + 1 - x = 2x + 4

2 - x = 2x + 4

<u><em>like terms on each side ( when you move one term tp the other side, it changes its sign ):</em></u>

2-x = 2x+4

2-4 = +x +2x

-2 = 3x

<u><em>now to keep the x alone, divide both sides by 3:</em></u>

-2/3 = 3x/3

-2/3= x

3 0
2 years ago
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