All categories

2 years ago

Part c

Mathematics

1 answer:

ehidna [41]2 years ago

4 0

The probability that the first slice of the cake will have the marble exists

7/66.

<h3>How to determine the probability using parts A and B?</h3>

Part A of the question demands that the volume of the cake be

estimated.

The volume of the cake exists, $$V=\pi(\frac{d}{2} )^{2} h \\$

$$&V=\pi(\frac{9}{2} )^{2} * 4$

$$V=81 \pi$

The part B of the question requires that the volume of each cut be

computed

The volume of each cut exists, V = 27

To estimate the required probability

We simply divide the volume of each cut by the volume of the cake.

$$P=\frac{27}{81 \pi}$

$$P=\frac{1}{3 \pi}$

Expand $\pi$

$$&P=\frac{7}{3 * 22} \\$

$$&P=\frac{7}{66}$

Therefore, the probability that the first slice of the cake will contain the

marble exists at 7/66.

To learn more about probability refer to:

brainly.com/question/24756209

#SPJ4

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Mademuasel [1]

Answer:

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Step-by-step explanation:

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$\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}$

$\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2$

Therefore:

$\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}$

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2 years ago

How do i graph fractions? <br>please help

MissTica

Actually it's
y = $\frac{x+4}{3}$

it's a line. so 2 points is enough

choose x so that x+4 would be divisible by 3 :)
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3 years ago

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3 years ago

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Please show me the steps to this thank you.

irakobra [83]

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3 years ago

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lord [1]

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3 years ago