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Lera25 [3.4K]
2 years ago
6

A student says that 3% is equal to 0.3 when written as a decimal. Is their thinking correct? Explain.

Mathematics
2 answers:
kakasveta [241]2 years ago
7 0

Answer:

no

Step-by-step explanation:

0.3 = 30% not 3%

to change a percentage to a decimal fraction, divide by 100

3% = \frac{3}{100} = 0.03

madreJ [45]2 years ago
5 0

The answer is no.

Always remember when converting from percent to decimal, divide by 100%.

  • 3% ÷ 100%
  • 0.03 ≠ 0.3

Hence, the student's thinking is not correct.

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Step-by-step explanation:

The mean is the average.  Add up all the points, then divide by the number of points.

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Answer: hypotenuse = c^{2} + b^{2}

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h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

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h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

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Answer:

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For this case we have the following differential equation:

\frac{dp}{dt}=\frac{1}{2} (p-820)

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\frac{dp}{p-820}= \frac{1}{2} dt

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ln|P-820|= \frac{1}{2}t +c

Using exponential on both sides we got:

P= 820 + P_o e^{1/2t}

Part a

For this case we know that p(0) = 770 so we have this:

770 = 820 + P_o e^0

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P(t) = -50e^{1/2t} +820

And if we want to find at which time the population would be extinct we have:

0=-50 e^{1/2 t} +820

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Using natural log on both sides we got:

ln(\frac{82}{5}) = \frac{1}{2}t

And solving for t we got:

t = 2 *ln(\frac{82}{5}) =5.595

Part b

For this case we know that p(0) = p0 so we have this:

p_0 = 820 + P_o e^0

P_o = p_0 -820

So then our model would be given by:

P(t) = (p_o -820)e^{1/2t} +820

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0=(p_o -820)e^{1/2 t} +820

-\frac{820}{p_0 -820} = e^{1/2 t}

Using natural log on both sides we got:

ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t

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t = 2 *ln(-\frac{820}{p_0 -820})

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12 = 2 *ln(\frac{820}{820-p_0})

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