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Nostrana [21]
2 years ago
7

I need help please?!!!!

Mathematics
1 answer:
taurus [48]2 years ago
4 0

The multiplicative inverse of a number x is a number y such that their product xy is 1.

So, we want a number such that

10\cdot x = 1

Divide both sides by 10:

x=\dfrac{1}{10}

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The four rectangles shown have different side lengths.
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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
Please help me find x
Ghella [55]

Answer:

x = 53

Step-by-step explanation:

Remember that the sum of all 3 interior angles in a triangle is 180∘ so

74 + x + x = 180

74 + 2x = 180

2x = 180 - 74

2x = 106

x = 106/2

x = 53

3 0
3 years ago
Read 2 more answers
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