Question

ASAP PLEASE please please

Answer 1

Answer:

$b=\dfrac{8}{3}$

Step-by-step explanation:

Given equation:

$\dfrac{1}{b}+10=\dfrac{9}{b}+7$

Subtract 10 from both sides:

$\implies \dfrac{1}{b}+10-10=\dfrac{9}{b}+7-10$

$\implies \dfrac{1}{b}=\dfrac{9}{b}-3$

Multiply both sides by b:

$\implies \dfrac{1 \cdot b}{b}=\dfrac{9 \cdot b}{b}-3b$

$\implies 1=9-3b$

Add 3b to both sides:

$\implies 1+3b=9-3b+3b$

$\implies 3b+1=9$

Subtract 1 from both sides:

$\implies 3b+1-1=9-1$

$\implies 3b=8$

Divide both sides by 3:

$\implies \dfrac{3b}{3}=\dfrac{8}{3}$

$\implies b=\dfrac{8}{3}$

Answer 2

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

$\qquad \sf \dashrightarrow \: \cfrac{1}{b} + 10 = \cfrac{9}{b} + 7$

$\qquad \sf \dashrightarrow \: \cfrac{9}{b} - \cfrac{1}{b} = 10 - 7$

$\qquad \sf \dashrightarrow \: \cfrac{8}{b} = 3$

$\qquad \sf \dashrightarrow \: b = \cfrac{8}{3}$