\left[a \right] = \left[ -4+\frac{ - ax}{3}+\frac{\left( -4\right) \,x}{3}\right][a]=[−4+3−ax+3(−4)x]
F(x) = -3x² + 6x - 2
First, we make the coefficient of x² equal to 1
f(x) = -3(x² + 2x - 2/3)
Now, we must make the form a² + 2ab + b²
b = 2x/2x
b = 1
f(x) = -3(x² + 2x + 1² - 1² - 2/3)
f(x) = -3(x² + 2x + 1 - 5/3)
f(x) = -3(x + 1)² - 5
The vertex is (-1 , -5)
And this is the maximum point because the coefficient of the squared term is negative.
Answer:
every day i had to dig D amount of times minus 5 hours for break
Step-by-step explanation:
Answer:
No value
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Y has zero solutions
