Answer : option A
To find the range of scores that represents the middle 50 % of the student who took the test , we find inter quartile
Inter quartile range is the middle 50% of the given range of scores.
The difference between the upper quartile and lower quartile is the inter quartile that is middle 50%
From the diagram , we can see that
Upper quartile = 89
lower quartile = 65
So range is 65% to 89%
Answer:
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Step-by-step explanation:
x³+216y³+8z³-36xyz
x³+(6y)³+(2z)³-3×6×2×xyz
As we know
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
Let a=x
b=6y
c=2z
Now.
[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]
[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]
Answer:
-1/16
-1/4
1
-4
16
Step-by-step explanation:
Put x as -4 and solve.
-4^-2 = 1/-4^2 = -1/16
-4^-1 = 1/-4 = -1/4
-4^0 = 1
-4^1 = -4
-4^2 = 16
