For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:
The given line is:
So we have:
We find
So, a line perpendicular to the one given is of the form:
We substitute the given point to find "b":
Finally we have:
In point-slope form we have:
ANswer:
The slope of a graph is rise over run. So count how many units up you move and put that over how many units right you move. If you are moving down or to the left it would be negative.
Tonne is a metric unit equal to 1000 kilograms.
If the line segment is perpendicular to a line with the slope of -4, that means the line segment has a slope of 1/4.
First let's make an equation for the line segment using the slope of 1/4 and the point at (2,6) to find the final piece, the y-intercept
y = mx + b
6 = 1/4(2) + b
6 = 2/4 + b
24/4 = 2/4 + b
22/4 = b
y = 1/4 x + 22/4
6 = 1/4(2) + 22/4
6 = 2/4 + 22/4
6 = 24/4
6 = 6 <-- proves that this equation is correct
Now you may plug in the x to find y. ( 8 , y )
y = 1/4(8) + 22/4
y = 8/4 + 22/4
y = 30/4 = 15/2 = 7.5
Answer:
12 - 3 y ÷ 2 + y( 2 y - 4 ÷ y ) = 21.51.
Step-by-step explanation:
Here, the given expression is:
12 - 3 y ÷ 2 + y( 2 y - 4 ÷ y )
Now, we need to evaluate the given expression for y = 3
12 - 3 y ÷ 2 + y( 2 y - 4 ÷ y ) by the rule of BODMAS
12 - 3 y ÷ 2 + y( 2 y - 4 ÷ y ) = 12 - 3(3) ÷ 2 + 3(2(3) -4 ÷ 3)
= 12 - 9 ÷ 2 + 3( 6 - 4 ÷ 3)
= 12 - <u>9</u><u> ÷ 2</u> + 3( 6 - <u>4 ÷ </u><u>3</u>)
= 12 - <u>4.5</u> + 3( 6 - <u>1.33</u>)
= 7.5 + 3(4.67)
= 7.5 + 14.01
= 21.51
So, 12 - 3 y ÷ 2 + y( 2 y - 4 ÷ y ) for y = 3 is 21.51.