Given :
Han says that we can wrap a 5 foot rope around a wheel with a 2 foot rope.
To Find :
It this true or false.
Solution :
Radius of wheel, r = 1 foot.
Circumference of wheel is given by :

Since, circumference is greater than 5 foot, therefore, we cannot wrap a 5-foot rope around a wheel with a 2-foot diameter.
Hence, this is the required solution.
Answer: $24
Step-by-step explanation:
Mariano saved $24because
120 x 0.2=24
She payed $96
Since there are

in a circle, and central

, you can see that the part "sliced out" by the central angle is

of the whole circle.
This means that the length of the intercepted arc

is

of the circumference of the circle. So,
Answer:
Step-by-step explanation:
If Δ JKL ~ Δ JHG , then
=
≠
⇒ triangles are not similar
4 500-60 = 4 440
4 440/38 = 116.8
At most they would be able to invite 116 people to the reception with their budget.