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amid [387]
2 years ago
6

How many grams of al2br6 form when 6. 00 moles of bromine react completely?

Chemistry
1 answer:
Solnce55 [7]2 years ago
8 0

2.67×10^{2}g  of Al_{2} Br_{6} form when 6. 00 moles of bromine react completely.

As per the chemical equation 2 moles of Aluminum react with 3 moles of Bromine to generate 2 moles of Aluminum Bromide

Molecular Weight of Al= 27 g/mol

Molecular Weight of Bromine= 159.8 g/mol

Molecular Weight of Aluminum Bromide= 266.7 g/mol

So,

Moles of Br = 6 moles

Moles of Al  = \frac{2}{3} * 6 = 4moles

similarly,

moles of Al_{2} Br_{6} = \frac{1}{6} * 6 = 1mole

Moles of Al_{2} Br_{6}  =  \frac{weight}{molecular weight}

1 mole = \frac{weight}{266.7}

weight = 2.67×10^{2}g

Learn more about Aluminum Bromide here;

brainly.com/question/19459538

#SPJ4

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