Question

How many grams of al2br6 form when 6. 00 moles of bromine react completely?

Answer 1

2.67×$10^{2}$g  of $Al_{2} Br_{6}$ form when 6. 00 moles of bromine react completely.

As per the chemical equation 2 moles of Aluminum react with 3 moles of Bromine to generate 2 moles of Aluminum Bromide

Molecular Weight of Al= 27 g/mol

Molecular Weight of Bromine= 159.8 g/mol

Molecular Weight of Aluminum Bromide= 266.7 g/mol

So,

Moles of Br = 6 moles

Moles of Al  = $\frac{2}{3} * 6$ = 4moles

similarly,

moles of $Al_{2} Br_{6}$ = $\frac{1}{6} * 6$ = 1mole

Moles of $Al_{2} Br_{6}$  =  $\frac{weight}{molecular weight}$

1 mole = $\frac{weight}{266.7}$

weight = 2.67×$10^{2}$g

Learn more about Aluminum Bromide here;

brainly.com/question/19459538

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