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ELEN [110]
3 years ago
6

Choose all the answers that apply. Sulfuric acid is found in acid rain. Its chemical formula is H2SO4. Which of the following is

true of sulfuric acid?
It has two atoms of hydrogen.
It has one atom of sulfur
it has two atoms of helium.
It has four atoms of sulfuric oxide.
It has four atoms of oxygen.
Chemistry
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

Looks like 2 hydrogen and sulfuric oxide 4

You might be interested in
Fill in the coefficients that will balance the following reaction: a0PbI4 + a1CrCl3 → a2PbCl4 + a3CrI3
nika2105 [10]
PbI₄ + CrCl₃ --> PbCl₄ + CrI₃

There is 1 Pb and Cr atom on both sides.
There are 3 Cl atoms on the left side and 4 on the right side.
There are 4 I atoms on the left side and 3 on the right side.

PbI₄ + 4CrCl₃ --> 3PbCl₄ + CrI₃
Cl atoms are now balanced

3PbI₄ + 4CrCl₃ --> 3PbCl₄ + 4CrI₃
All of the atoms are now balanced.

3PbI₄ + 4CrCl₃ --> 3PbCl₄ + 4CrI₃
5 0
3 years ago
Read 2 more answers
0.76 g of lead(2) nitrate was dissolvedin 50.00ml of water a d treated with 25.00 ml of 0.2010M sodium sulfate inoder to determi
butalik [34]

Answer:

Mass of precipitate (PbSO₄) formed = 0.696 g

Explanation:

The reaction of Lead II Nitrate and Sodium Sulfate is given as

Pb(NO₃)₂ (aq) + Na₂SO₄ (aq) → 2NaNO₃ (aq) + PbSO₄ (s)

The precipitate from this reaction is the PbSO₄

0.76 g of Pb(NO₃)₂ is available for reaction, we convert to number of moles

Number of moles = (Mass)/(Molar Mass)

Mass = 0.76 g

Molar mass of Pb(NO₃)₂ = 331.2 g/mol

Number of moles of Pb(NO₃)₂ = (0.76/331.2) = 0.002294686 moles = 0.002295 moles

25.00 ml of 0.2010M sodium sulfate is available for the reaction, we also conert to number of moles.

Number of moles = (Concentration in mol/L) × (Volume in L)

Concentration of Na₂SO₄ in mol/L = 0.201 M

Volume of Na₂SO₄ in L = (25/1000) = 0.025 L

Number of moles of Na₂SO₄ = 0.201 × 0.025 = 0.005025 moles

From the stoichiometric balance of the reaction, 1 mole of Pb(NO₃)₂ reacts with 1 mole of Na₂SO₄

Hence, this indicates that Pb(NO₃)₂ is the limiting reagent as it is in short supply and it will therefore dictate the amount of precipitate (PbSO₄) formed.

1 mole of Pb(NO₃)₂ gives 1 mole of the precipitate (PbSO₄)

0.002295 mole of Pb(NO₃)₂ will give 0.002295 mole of the precipitate (PbSO₄)

Mass = (Number of moles) × (Molar mass)

Number of moles of precipitate (PbSO₄) formed = 0.002295 mole

Molar mass of PbSO₄ = 303.26 g/mol

Mass of precipitate (PbSO₄) formed = 0.002295 × 303.26 = 0.6958864734 = 0.696 g

Hope this Helps!!!

7 0
3 years ago
My Teacher didn't teach us this please help
oksian1 [2.3K]

Answer:

first; why is it a question if teacher never teached you it LOL anyways..

Explanation:

i would say its the second one

"The smae quality of each element is present on both sides of the equation."

5 0
3 years ago
the mass by mass percentage of a solution is 20%. find the mass of the solute dissolved in 500g of solution​
GuDViN [60]

Answer:

m_{solute}=100g

Explanation:

Hello,

In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:

\%m/m=\frac{m_{solute}}{m_{solution}}*100\%

We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:

m_{solute}=\frac{m_{solution}*\%m/m}{100\%} =\frac{500g*20\%}{100\%}\\ \\m_{solute}=100g

Best regards.

6 0
3 years ago
A sample of nitrogen gas occupies 1.55 L at
34kurt

Answer:

The new volume after the temperature reduced to -100 °C is 0.894 L

Explanation:

Step 1: Data given

Volume of nitrogen gas = 1.55 L

Temperature = 27.0 °C = 300 K

The temperature reduces to -100 °C = 173 K

The pressure stays constant

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of the gas = 1.55 L

⇒with T1 = the initial temperature = 300 K

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the reduced temperature = 173 K

1.55 L / 300 K = V2 / 173 K

V2 = (1.55L /300K) * 173 K

V2 = 0.894 L

The new volume after the temperature reduced to -100 °C is 0.894 L

3 0
2 years ago
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