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ELEN [110]
3 years ago
6

Choose all the answers that apply. Sulfuric acid is found in acid rain. Its chemical formula is H2SO4. Which of the following is

true of sulfuric acid?
It has two atoms of hydrogen.
It has one atom of sulfur
it has two atoms of helium.
It has four atoms of sulfuric oxide.
It has four atoms of oxygen.
Chemistry
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

Looks like 2 hydrogen and sulfuric oxide 4

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Sulfuric acid was once produced through the reaction of sulfur trioxide with water. Sulfur trioxide can form through the reactio
vekshin1

Answer 1) In the given reaction of sulfuric acid


2NO_{(g)} + O_{2}_{(g)} ---->  2NO_{2}_{(g)}


2NO_{2}_{(g)} + 2SO_{2}_{(g)} ---->  2NO}_{(g)} + 2SO_{3}_{(g)}


On addition of nitrogen monoxide gas the reaction rate increases and more amount of product is formed.


So, it is clear that NO is the catalyst in this reaction.


Answer 2) This can be proven that NO is catalyst because it increases the rate of the reaction, but it is not consumed during the reaction, and it also gets regenerated at the end of reaction.


Hence, nitrogen mono oxide is considered as the catalyst in the given reaction.


Answer 3) It increases the rate of reaction by decreasing the activation energy of the reaction. Also it can be clearly seen in this reaction the NO is reacting with oxygen to lower the energy of activation. So, it is providing an alternative pathway for proceeding the reaction. This all confirms the assumptions of NO being the catalyst.


2NO_{(g)} + O_{2}_{(g)} ---->  2NO_{2}_{(g)}

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How many objects in the solar system have been confirmed to currently support life?
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2) A balloon was inflated to a volume of 5.0 liters at a temperature of
TEA [102]

Answer:

6.12 L

Explanation:

Given that,

Initial volume, V₁ = 5 L

Initial temperature, T₁ = 7.0°C = 343 K

Final temperature, T₂ = 147°C = 420 K

We need to find its new volume. The relation between volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{5\times 420}{343}\\\\V_2=6.12\ L

So, the new volume is 6.12 L.

8 0
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