Question

Write the equation of the line that passes through

Answer 1

$y=\frac{x}{7} +\frac{15}{7}$

How to find the equation of a passing line?

• The equation y = mx often denotes a straight line with a gradient of m that passes through the origin. Y = mx is the equation for a straight line with gradient m that passes through the origin.

Given:  $(-1,2)$ and $(6,3).$

The slope of the line passing through$(x1,y1)$ $(x2,y2)$ is $\frac{y^{2} }{x^{2} } -\frac{y^{1} }{x^{1} }$

The slope of our line$=\frac{(3-2)}{(6+1)} =\frac{1}{7}$

Slope intercept from the equation would be $y= 1/7 x +C$

Find C:

Since $(-1,2)$ lies on the line, substitute these in the line equation

$2 = \frac{1}{7(-1)} +c$

$C=2+\frac{1}{7} =\frac{15}{7}$

Therefore, the equation in slope intercept form is$y=\frac{x}{7} +\frac{15}{7}$

To learn more about the Equation of a passing line, refer to:

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