Brent bought shirts for $50. Each shirt cost $10. How many shirts did he buy?

On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (2.4, negative 51) and a maximum value of (negat

Dvinal [7]

Answer:

b

Step-by-step explanation:

7 0

3 years ago

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What is the perimeter?and how to I find it

Lelechka [254]

Answer:

is there more info? I don't think this can be solved with given numbers could you take a more zoomed out photo?

5 0

3 years ago

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According to Inc, 79% of job seekers used social media in their job search in 2018. Many believe this number is inflated by the

Fynjy0 [20]

Answer:

Null hypothesis: $p\leq 0.79$

Alternative hypothesis: $p > 0.79$

$z=\frac{0.849 -0.79}{\sqrt{\frac{0.79(1-0.79)}{370}}}=2.786$

$p_v =P(z>2.786)=0.00267$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true proportion is higher than 0.79.

Step-by-step explanation:

1) Data given and notation

n=750 represent the random sample taken

X=314 represent the respondents that use social media in their job search.

$\hat p=\frac{314}{370}=0.849$ estimated proportion of respondents that use social media in their job search

$p_o=0.79$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is hgiher than 0.79.:

Null hypothesis: $p\leq 0.79$

Alternative hypothesis: $p > 0.79$

When we conduct a proportion test we need to use the z statisticc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.849 -0.79}{\sqrt{\frac{0.79(1-0.79)}{370}}}=2.786$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.786)=0.00267$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the true proportion is higher than 0.79.

7 0

3 years ago

What is the result of subtracting the secound equation from the first -4x-2y=-2 x-2y=9

crimeas [40]

Answer:

When we subtract the second equation x-2y=9 from the first equation 4x-2y=-2, we get the value of x = 11/5.

Therefore, the required result is:

x = 11/5

Step-by-step explanation:

Given

The first equation

$-4x-2y=-2$