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2 years ago

PLEASE HELP IK ITS SO HARD TO UNDERSTAND FOR MEEE

Mathematics

1 answer:

Minchanka [31]2 years ago

4 0

Answer: 15

Step-by-step explanation:

First step is to find the slope of the line given

y = -x - 2

y = mx + c where m is the slope of the line so the slope of the line is -1

If 2 lines are perpendicular to one another, the product of the slopes is -1 so the slope of the perpendicular line is -1/-1 = 1

y = 1x + c or y = x + c

As the line passes through the coordinate (-5,10), we can substitute the x and y value of the coordinates into the equation

10 = -5 + c

c = 15

So the equation of the line is y = x + 15

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Pls help i am confused no links

Juliette [100K]

Answer:

x = 20

Step-by-step explanation:

These angles are equal to each other because they are vertical angles.

Hence, we can equal the two measurements together to solve for x:

3x + 50 = 6x - 10

3x + 60 = 6x

60 = 3x

20 = x

Check your work:

3(20) + 50 = 6(20) - 10

60 + 50 = 120 - 10

110 = 110

Correct

3 0

2 years ago

Can someone answer this

rosijanka [135]

Answer:

The slope is 1.

Step-by-step explanation:

Remember:

$m = \frac{y_2 - y_1 }{x_2 - x_1}$

Let's plug in!

$m = \frac{ 9 - 4}{4 - ( -1)} = \frac{ 5}{ 5} = 1$

4 0

3 years ago

Read 2 more answers

What is the answer i cant solve it 6.4u-5.1u=-3.25?

Marta_Voda [28]

I hope this helps you

1,3 u = -3,25

1,3u ÷1,3 = -3,25 ÷ 1,3

u = -2,5

7 0

3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago

I am not very good at this can some one ☝️ help me and show work number 2

Galina-37 [17]

I know for a fact that the Airjet Express had shorter flight times because it had lesser dots than the Cross Country Airlines. Hope this helped!

6 0

3 years ago