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Nadusha1986 [10]
2 years ago
12

I WILL MARK 5 STARS! PLSSS FAST! At noon, the temperatures in Portland, Maine and Phoenix, Arizona had opposite values. The temp

erature in Portland was lower than in Phoenix. What was the temperature in each city? Explain your reasoning.
Mathematics
1 answer:
Marta_Voda [28]2 years ago
3 0

At noon, the temperatures in Portland, Maine and Phoenix, Arizona had opposite values. is mathematically given as

  • PoT=-PhT
  • PhT =+PoT

<h3> What was the temperature in each city?</h3>

Generally, the equation  for the temperature at Portland, Maine is mathematically given as

PoT=-PhT

Since  Portland, Maine and Phoenix, Arizona had opposite values. The temperature in Portland was lower than in Phoenix.

In conclusion, the temperature in each city is

PoT=-PhT

PhT =+PoT

Read more about temperature

brainly.com/question/11464844

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Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

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-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

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where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

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B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

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So, we have the following probabilities.

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- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

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Given w= weight of a trout.

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