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galina1969 [7]
3 years ago
7

Một lô hàng chứa rất nhiều sản phẩm, trong đó tỷ lệ sản phẩm loại tốt là 70%. chọn ngẫu nhiên từ lô hàng ra 5 sản phẩm. gọi X là

số sản phẩm tốt có trong 5 sản phẩm chọn ra.
a. hãy tìm bảng phân phối xác xuất của X
b. xác định kỳ vọng và phương sai của X
c. tìm số sản phẩm tốt được lấy ra có khả năng xảy ra nhiều nhất
Mathematics
1 answer:
den301095 [7]3 years ago
8 0

trả lời : lâp bảng

X=0 thì xác suất lấy ra được sản phẩm tốt là 5*30%=1,5%

X =1 thì xác suất lấy ra được là 1* 70%*4*30%=0,84%

X=2 thì xác suất lấy ra được sản phẩm tốt là 2*70%*3*30%=1,26%

X=3 thì xác suất lấy ra được sản phẩm tốt là 3*70%*2*30%=1,26%

X=4 thì xác suất lấy ra được sản phẩm tốt là 4*70%*1*30%=0,84%

X=5 thì xác suất lấy ra được sản phẩm tốt là 5*70%=3,5%

X 0 1 2 3 4 5

P 1,5 0,84 1,26 1,26 0,84 3,5

b,

E(x)= 1,5*0+ 0,84*1+1,26*2+1,26*3+0,84*4+3,5*5=28

E(x^2)=1,5*0^2+0,84*1^2+1,26*2^2+1,26*3^2+0,84*4^2+3,5*5^2=118,16

===> V(x)= (E(x))^2-E(x^2)=28^2-118,16=665,84

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