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boyakko [2]
3 years ago
6

Which expression is equivalent to -5(-6h +8 - 12)?

Mathematics
1 answer:
Grace [21]3 years ago
5 0
30h-40+60 or 30h+20 I think
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Which of the following is the equation for the graph shown?
Grace [21]

Answer:

x squared over 5 plus y squared over 30 equals 1

Step-by-step explanation:

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3 years ago
Use the equation to answer the following question y=(x-3(x+2)/(x+4)(x-4)(x+2)
givi [52]

Answer:

See below

Step-by-step explanation:

The given rational function is;

y=\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}

The given function is not continuous where the denominator is equal to zero.

(x+4)(x-4)(x+2)=0

The function is discontinuous at x=-4,x=4,x=-2

b) The point at x=-2 is a removable discontinuity(hole) because (x+2) is common to both the numerator and the denominator.

The point at x=-4 and x=4 are  non-removable discontinuities(vertical asymptotes)

c) The equation of the vertical asymptotes are x=-4 and x=4

To find the equation of the horizontal asymptote, we take limit to infinity.

\lim_{x\to \infty}\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}=0

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8 0
3 years ago
What is the single matrix that would transform a pre-image according to the following (in order):
IgorLugansk [536]

Step-by-step explanation:

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6 0
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What is the correct answer ro this problem? 121 ÷ 11 = ?​
Anon25 [30]

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3 years ago
Solve by quadratic formula: <br> 8a2 + 6a + 5=0
Veseljchak [2.6K]

Answer:

x = \frac{-3 \pm i\sqrt{31}}{8}

Step-by-step explanation:

Quadratic Formula: x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

√-1 is imaginary number i

Step 1: Define Quadratic

8a² + 6a + 5 = 0

a = 8

b = 6

c = 5

Step 2: Plug into Quadratic Formula

x = \frac{-6 \pm \sqrt{6^2-4(8)(5)} }{2(8)}

Step 3: Solve

x = \frac{-6 \pm \sqrt{36-160} }{16}

x = \frac{-6 \pm \sqrt{-124} }{16}

x = \frac{-6 \pm \sqrt{124} (\sqrt{-1} )}{16}

x = \frac{-6 \pm i\sqrt{124}}{16}

x = \frac{-6 \pm 2i\sqrt{31}}{16}

x = \frac{2(-3 \pm i\sqrt{31})}{16}

x = \frac{-3 \pm i\sqrt{31}}{8}

8 0
4 years ago
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