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andrey2020 [161]
4 years ago
5

Solve for x. x^2−3x−70=0 x^2 is x to the second power

Mathematics
2 answers:
mr_godi [17]4 years ago
7 0
<span>x^2−3x−70=0
(x - 10)(x + 7) = 0
x - 10 = 0; x =10
x + 7 =0; x = -7

answer
x = -7 and x = 10</span>
timurjin [86]4 years ago
3 0
X² <span>− 3x − 70=0
</span>x² + 7x - 10x − 70=0
x(x+7) - 10(x+7) = 0
(x+7)(x-10) = 0

x + 7 = 0   or   x - 10 = 0
x = -7              x = 10

Answer: x=-7,  x=10 
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What is the surface area of the square pyramid represented by the net below?
4vir4ik [10]

Answer:

64 cm^2

Step-by-step explanation:

Square: 4*4 = 16

Triangles: 4((4*6)/2))

       = 4(24/2)

       = 4(12)

       = 48

Add the square and triangles together

       = 16 + 48

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6 0
4 years ago
Can anybody help me figure out the area of simple composite figure?
zvonat [6]

Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

  • A=A_{1} +A_{2}

where,

A be the area of the given figure

A_{1} be the area of the rectangle

A_{2} be the area of the semicircle.

  • The area of the rectangle = lb where, l be the length and b be the width
  • Area of the semicircle = \frac{1}{2} \pi r^{2}, r be the radius of the semicircle.

Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

A_{1} = (16)(12) sq ft

or, A_{1} = 192 sq ft

A_{2} = \frac{1}{2} (3.14)(6^{2} ) sq ft

or, A_{2}=56.52 sq ft

So,

A = 56.52+192 sq ft

A = 248.52 sq ft

Rounding off to the nearest tenth, we get;

A=248.5 sq ft.

Hence,

The area of the composite figure is 248.5 sq ft.

7 0
3 years ago
(06.02) Translate the algebraic expression shown below into a verbal expression. (3 points) Fraction with variable x in numerato
lukranit [14]

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Product is multiplication.

Difference is subtraction.

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const2013 [10]

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Step-by-step explanation:

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3 years ago
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Answer:

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-5s = -q - 6r + 3

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4 0
3 years ago
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