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Papessa [141]
3 years ago
15

WILL GIVE BRAINLIEST. Tickets to a show cost $3 for students and $7 for adults. If 250 tickets were sold and ticket sales totale

d $1102, how many adult tickets were sold?
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

88 adult tickets were sold

Step-by-step explanation:

3s + 7a = 1102

(s + a = 250)-3

   3s + 7a = 1102

+ -3s - 3a = -750      Add these equations together

4a = 352                  Divide both sides by 4

a = 88

Now plug this into the second equation

s + a = 250

s + 88 = 250

  - 88     - 88        Subtract 88 from both sides

s = 162

If this answer is correct, please make me Brainliest!

ikadub [295]3 years ago
3 0

You're supposed to make two equations then subtract them but it comes out as a decimal

The second equation is made by the student ticket cost/3$ times the amount of tickets sold/250.

x+y=250--> 3x+3y=750

7x+<u>3y</u>=1102

<u>-3x-3y=750</u>

5x      =352

then 352/5=70.4

Idk if i did something wrong but this is what i got.

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Answer:

The answer is the proof so it is long.

The question doesn't define u(n), but it's not hard to guess.


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2) inverse: a' ∈ G, a∘a' = a'∘a = e,

3) closed: a∘b ∈ G,

4) associative: (a∘b)∘c = a∘(b∘c),

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Identity: e = 1. Clearly 1∘a = a∘1 = a. (a is already < n).


Closed: u(n) is closed for n prime. We must show that for all a, b ∈ u(n), the integer product ab is not divisible by n, so that ab ≢ 0 (mod n). Since n is prime, ab ≠ n. Since a < n, b < n, no factors of ab can equal prime n. (If n isn't prime, we already excluded from u(n) all integers sharing factors with n).


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Associative and Commutative:

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a∘b = b∘a because ab = ba.


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