1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Papessa [141]
2 years ago
15

WILL GIVE BRAINLIEST. Tickets to a show cost $3 for students and $7 for adults. If 250 tickets were sold and ticket sales totale

d $1102, how many adult tickets were sold?
Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
7 0

Answer:

88 adult tickets were sold

Step-by-step explanation:

3s + 7a = 1102

(s + a = 250)-3

   3s + 7a = 1102

+ -3s - 3a = -750      Add these equations together

4a = 352                  Divide both sides by 4

a = 88

Now plug this into the second equation

s + a = 250

s + 88 = 250

  - 88     - 88        Subtract 88 from both sides

s = 162

If this answer is correct, please make me Brainliest!

ikadub [295]2 years ago
3 0

You're supposed to make two equations then subtract them but it comes out as a decimal

The second equation is made by the student ticket cost/3$ times the amount of tickets sold/250.

x+y=250--> 3x+3y=750

7x+<u>3y</u>=1102

<u>-3x-3y=750</u>

5x      =352

then 352/5=70.4

Idk if i did something wrong but this is what i got.

You might be interested in
Item 4 Evaluate 8x−y2−3 when x=−1/4 and y=3 .
iren2701 [21]
8(-1/4)-(3)2-3=-2-6-3=-11
8 0
2 years ago
Read 2 more answers
Suppose that a random sample of 10 newborns had an average weight of 7.25 pounds and sample standard deviation of 2 pounds. a. T
frosja888 [35]

Answer:

z=\frac{7.25-7.5}{\frac{1.4}{\sqrt{10}}}=-0.565  

p_v =P(Z  

a) If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true average is not significantly less than 7.5.  

b) \chi^2 =\frac{10-1}{1.96} 4 =18.367  

p_v =P(\chi^2 >18.367)=0.0311

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 1.96.

Step-by-step explanation:

Assuming this info: "Suppose birth weights follow a normal distribution with mean 7.5 pounds and standard deviation 1.4 pounds"

1) Data given and notation  

\bar X=7.25 represent the sample mean  

s=1.2 represent the sample standard deviation

\sigma=1.4 represent the population standard deviation

n=10 sample size  

\mu_o =7.5 represent the value that we want to test  

\alpha=0.05,0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 7.5, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7.5  

Alternative hypothesis:\mu < 7.5  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{7.25-7.5}{\frac{1.4}{\sqrt{10}}}=-0.565  

4)P-value  

Since is a left tailed test the p value would be:  

p_v =P(Z  

5) Conclusion  

Part a

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true average is not significantly less than 7.5.  

Part b

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=10 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =4 represent the sample variance obtained

\sigma^2_0 =1.96 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance increase, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \leq 1.96

Alternative hypothesis: \sigma^2 >1.96

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{10-1}{1.96} 4 =18.367

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 9. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2 >18.367)=0.0311

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(18.367,9,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 1.96.

4 0
3 years ago
Please help im so lost​
qwelly [4]

Answer:

are you allowed to email your teacher about it

that's only if you are doing remote school

5 0
3 years ago
Parallelogram R S T U is shown. Angle S is 70 degrees.
olya-2409 [2.1K]

Answer:

<h3>B. m∠R = 110°, m∠T = 110°, m∠U = 70°</h3>

Step-by-step explanation:

The opposite angles of the parallelogram are the same.

From the diagram;

<S = <U and <R = <T

Given

<S = 70°

Since <S = <U, hence <U = 70°

Since the sum of angles in a quadrilateral is 360 degrees, hence;

<R+<S+<T+<U = 360

Since <R = <T, then;

<Y+<S+<T+<U = 360

2<T + 70+70 = 360

2<T = 360-140

2<T = 220

<T = 220/2

<T = 110°

Since <T = <R, then < R = 110°

Hence m∠R = 110°, m∠T = 110°, m∠U = 70°. Option B is correct

4 0
3 years ago
Read 2 more answers
Find the value of -7 -8-(-8) -7
kkurt [141]
The answer is 1 bro one
3 0
3 years ago
Read 2 more answers
Other questions:
  • Find the value of the sec 19 degrees using you calculator. (This might be a really simple question but I just don't know how to
    5·1 answer
  • Classify a triangle with vertices A(1, 1), B(4, 7), and C(7, 1) as one of the following.
    6·1 answer
  • The excluded values of a rational expression are 2 and 5. Which of the following could be this expression?
    8·1 answer
  • What is the slope of the line? ​
    12·2 answers
  • One length of a rectangular garden lies along a patio wall.​ However, the rest of the garden is enclosed by 28 feet of fencing.
    10·1 answer
  • What is the total weight, in pounds, of 100 sharks that each weigh 5.015× 10 (to the 3rd power) pounds
    10·1 answer
  • Find the area of 4,4,8,2
    8·2 answers
  • Round 523,837 to the nearest thousand
    8·2 answers
  • graph each system of equations to find its solution. then, prove that the caution is true In a check by substituting it into bot
    8·1 answer
  • The table shows the temperature (V) as different altitudes of). This is a linear relationship was the 0.00468 te dele The temper
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!