The pH a 0.25 m solution of C₆H₅NH₂ is equal to 3.13.
<h3>How do we calculate pH of weak base?</h3>
pH of the weak base will be calculate by using the Henderson Hasselbalch equation as:
pH = pKb + log([HB⁺]/[B])
pKb = -log(1.8×10⁻⁶) = 5.7
Chemical reaction for C₆H₅NH₂ is:
C₆H₅NH₂ + H₂O → C₆H₅NH₃⁺ + OH⁻
Initial: 0.25 0 0
Change: -x x x
Equilibrium: 0.25-x x x
Base dissociation constant will be calculated as:
Kb = [C₆H₅NH₃⁺][OH⁻] / [C₆H₅NH₂]
Kb = x² / 0.25 - x
x is very small as compared to 0.25, so we neglect x from that term and by putting value of Kb, then the equation becomes:
1.8×10⁻⁶ = x² / 0.25
x² = (1.8×10⁻⁶)(0.25)
x = 0.67×10⁻³ M = [C₆H₅NH₃⁺]
On putting all these values on the above equation of pH, we get
pH = 5.7 + log(0.67×10⁻³/0.25)
pH = 3.13
Hence pH of the solution is 3.13.
To know more about Henderson Hasselbalch equation, visit the below link:
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you add the masses of the reactants, because of conservation of mass. if there are two or more products they will ask you to find the mass of only one product or the sum of the mass of all products
Answer:
frequency of light = ![4.2\times 10^{-13}](https://tex.z-dn.net/?f=4.2%5Ctimes%2010%5E%7B-13%7D)
Explanation:
we know that relation between frequency and wavelength of light is
frequency × wavelength = speed of light.
therefore frequency = ![\frac{c}{wavelength}](https://tex.z-dn.net/?f=%5Cfrac%7Bc%7D%7Bwavelength%7D)
= ![\frac{3\times 10^{8}}{6.98\times 10^{-6}}](https://tex.z-dn.net/?f=%5Cfrac%7B3%5Ctimes%2010%5E%7B8%7D%7D%7B6.98%5Ctimes%2010%5E%7B-6%7D%7D)
=![4.2\times 10^{-13}](https://tex.z-dn.net/?f=4.2%5Ctimes%2010%5E%7B-13%7D)
Answer:
The atoms are ranked in decreasing order as follows:
Fluorine ---4
Carbon ----3
Boron ------2
Beryllium --1
Explanation:
Effective nuclear charge (Zeff) is defined as the difference between the actual nuclear charge (the atomic number, Z) and the shielding constant (S).
It is calculated by finding the atomic number and electronic configuration, attributing a shielding value to each electron, adding all the shielding values and using the formula:
Z eff = Z - S
Effective nuclear charges:
An atom of carbon: 3.25
An atom of fluorine: 5.20
An atom of beryllium: 1.95
An atom of boron: 2.60
Answer:
The amount of gas is what I came up with