Pulmonary ventilation, and carbonic acid-bicarbonate buffering system
We can use two equations for this problem.<span>
t1/2 = ln
2 / λ = 0.693 / λ
Where t1/2 is the half-life of the element and λ is
decay constant.
20 days = 0.693 / λ
λ = 0.693 / 20 days
(1)
Nt = Nο eΛ(-λt) (2)
Where Nt is atoms at t time, No is the initial amount of substance, λ is decay constant and t is the time
taken.
t = 40 days</span>
<span>No = 200 g
From (1) and (2),
Nt = 200 g eΛ(-(0.693 / 20 days) 40 days)
<span>Nt = 50.01 g</span></span><span>
</span>Hence, 50.01 grams of isotope will remain after 40 days.
<span>
</span>
Answer:
Density is 6.16g/L
Explanation:
<em>... at exactly -15°C and exactly 1atm...</em>
<em />
Using general gas law:
PV = nRT
We can find density (Ratio of mass and volume) in an ideal gas as follows:
P/RT = n/V
<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>
n*MW = m
n = m/MW
P/RT = m/V*MW
P*MW/RT = m/V
<em>Where P is pressure: 1atm;</em>
<em>MW of chlorine pentafluoride: 130.445g/mol</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>
<em />
Replacing:
P*MW/RT = m/V
1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V
6.16g/L = m/V
<h3>Density of the gas is 6.16g/L</h3>
<em> </em>
Chemical weathering is when things get weathered chemically
And an endothermic reaction, always treat heat as a reactant
