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Katena32 [7]
2 years ago
12

The area of a rectangular cocktail table is x^2-18x+32 If the width is x-16 what is its length?

Mathematics
1 answer:
Paraphin [41]2 years ago
6 0

Answer: (x-2)

Step-by-step explanation:

This problem is a middle-term factorization, or factoring by splitting the middle term.

We have the equation

x^2 - 18x + 32

This equation represents the area, and area = length x width for all rectangles. We also know the width, x-16, which makes it easier for us. The length must also be in the same format.

x^2 - 18x + 32

= x^2 - 16x - 2x + 32

= x(x-16) - 2(x - 16)

= (x-16) (x-2) -------> we get this through taking (x-16) common

We could also pretend that the length is x - y, where y is the number we need to finish the equation.

x^2 - 18x + 32

= (x-16) (x-y)

= x^2 -16x - xy + 16y

-16 minus 2 is -18, which is our middle term.

Therefore, y = 2. This is also verified because is 16y = 32, the constant term, then through transposing we get y = 2.

Our answer is that the length is (x-2).

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almond37 [142]

Answer: The correct congruence statement is \triangle QDJ\cong \triangle MCW.

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Draw two triangles according to the given information.

From the figure it is noticed that

QD\cong MC

DJ\cong CW

QJ\cong MW

So by SSS rule of congruence we can say that \triangle QDJ\cong \triangle MCW.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!! TRIG, Theres a picture!!
BartSMP [9]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

3(  { \tan }^{2} \theta -    { \sec }^{2}  \theta)

Using trigonometric identities

That's

1 + { \tan }^{2} \theta  =   { \sec }^{2}  \theta

Rewrite the expression

That's

3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\

Simplify

We have

3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)

So we have

3( - 1)

We have the final answer as

<h2>- 3</h2>

Hope this helps you

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For this case we propose a system of equations:

x: Variable that represents the amount of hours that Olivia's mother drove

y: Variable that represents the amount of hours that Olivia's father drove

So, we have:

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From the first equation we have:

x = 14-y

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Answer:

(x, y) :( 11,3)

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