I have the best ans and that is
Let Marc's age be x. If Jeanine is twice as old as Marc, then her age will be 2x. If their ages added together are 24, then you can create the following equation:
2x + x = 24
3x = 24
x = 8
Remember that x is Marc's age. So if Marc is 8, and Jeanine is twice as old, she will be 16.
Answer:
D: 6 5/6
Step-by-step explanation:
Solve for a:
a + 7/6 = 8
Put each term in a + 7/6 over the common denominator 6: a + 7/6 = (6 a)/6 + 7/6:
(6 a)/6 + 7/6 = 8
(6 a)/6 + 7/6 = (6 a + 7)/6:
(6 a + 7)/6 = 8
Multiply both sides of (6 a + 7)/6 = 8 by 6:
(6 (6 a + 7))/6 = 6×8
(6 (6 a + 7))/6 = 6/6×(6 a + 7) = 6 a + 7:
6 a + 7 = 6×8
6×8 = 48:
6 a + 7 = 48
Subtract 7 from both sides:
6 a + (7 - 7) = 48 - 7
7 - 7 = 0:
6 a = 48 - 7
48 - 7 = 41:
6 a = 41
Divide both sides of 6 a = 41 by 6:
(6 a)/6 = 41/6
6/6 = 1:
Answer: a = 41/6 or a= 6 5/6
Multiply 11 yards by 7 yeards and you will get ur answrr
