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3 years ago

63x19 estimate and choose method

Mathematics

2 answers:

allsm [11]3 years ago

7 0

Answer:

1197

Step-by-step explanation:

63 x 19 = 1197

Can you mark me brainliest

Anuta_ua [19.1K]3 years ago

4 0

Answer:

1200 would be an estimate

Step-by-step explanation:

Rounding to the nearest 10's digits would be a method of estimation. For example, in this case, 63 would round down to 60 and 19 would round up to 20 for a quick estimate. 60 times 20 = 1200

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A teacher asks students to list the math lessons they learned on nine random school days in the past month. She evaluates the st

zysi [14]

Answer:

Simple random sampling

Step-by-step explanation:

Hope this work :)

5 0

2 years ago

Please help me. this is hard

allochka39001 [22]

Since it is a square that means each side is equal.
The perimeter is 24, and since there is four sides we would divide it by four to find the length of each side.

24/4 = 6

Each side is 6.
By looking at the picture, one side of the square, is the length of the radius.

The radius of the square is 6.

The only thing left to do is to find the circumference.
The circumference formulas are:

C = $\pi$ d
C = 2 $\pi$ r

We can use the first one Diameter x pi (3.14)
To find the diameter we would just multiply the radius by two.

6 x 2 = 12

Diameter = 12

So multiply it by pi

12 x 3.14 = 37.68
or D 12 $\pi$

7 0

3 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago

Solve the system of equations by substitution method

mina [271]

( - 0.625, - 1.75 )

so since the first equation is already simplified , just replace it in the second equation

6 0

3 years ago

(3p+5)(2) simplified

Vsevolod [243]

Multiply each term in the parentheses by 2
3p x 2 +5 x2

Calculate the product
6p+5 x 2

Multiple the number
6p x 10

That’s your answer
6p x 10

8 0

3 years ago