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1 year ago

Find the size of each of the angles marked with letter

Mathematics

1 answer:

lilavasa [31]1 year ago

4 0

Answer:

f = 78 , g = 32 , h = 74

Step-by-step explanation:

f and 78° are alternate angles and are congruent , then

f = 78

---------------------------

h and 74° are alternate angles and are congruent , so

h = 74

--------------------------

the sum of the 3 angles in the triangle = 180°

sum the 3 angles and equate to 180

78 + g + h = 180

78 + g + 74 = 180

152 + g = 180 ( subtract 152 from both sides )

g = 28

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Answer:

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Step-by-step explanation:

Pro por tions:

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8 0

2 years ago

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Gemiola [76]

Answer:

$x=2\sqrt{6}$

Step-by-step explanation:

Use the Pythagorean theorem:

$a^2+b^2=c^2$

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$\sqrt{10}^2+\sqrt{14}^2=x^2$

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3 0

3 years ago

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He bought 4 books.

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If he bought 3 magazines, m =3
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2 years ago

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Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

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3 years ago

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olga nikolaevna [1]

Answer:

Step-by-step explanation:

6 0

2 years ago

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Find the size of each of the angles marked with letter​

Find the size of each of the angles marked with letter