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Vlad1618 [11]
1 year ago
15

Need step by step detailed answer

Mathematics
1 answer:
kolezko [41]1 year ago
4 0

Answer:

y = -4x - 4

Step-by-step explanation:

If we have two lines in slope intercept form as

y = m_1x + c_1 \text{ and}\\y = m_2x + c_2\\

then the product of the slopes m_1m_2 = -1

In other words, m_2 = -\frac{1}{m_1}

We have the first line as

y = \frac{1}{4}x + 5\\\\

The slope of this line is \frac{1}{4}

The slope of a perpendicular line will be the negative of the reciprocal of this line

Reciprocal of 1/4 is 4

So slope of perpendicular line is -4 which implies

y = -4x + c

We have to determine c

Since the line passes through (-3, 8), plug in these values for x and y in the equation and solve for c

8 = (-4)(-3) + c

8 = 12 + c

c = -4

So the equation of the perpendicular line is y = -4x - 4 (Answer)

It is always a good idea to plot these graphs and see if they fit the data provided

The attached plot shows the two graphs and you can see they are perpendicular to each other and the perpendicular line(the answer) passes through point (-3,8)

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How can I work it out to find the product of 7-3,7
romanna [79]
You should do 7-3=4 then do what’s u have to do with the 7
6 0
3 years ago
6) What are ED and FD?
kolezko [41]

Answer:

ED = 12 and FD = 24

Step-by-step explanation:

See the attached diagram.

The perpendicular distance between the three parallel lines are same i.e. AB = BC = 8

Therefore, the parallel lines will divide any transverse line ( say FD ) in 1 : 1 ratio i.e. will divide equally.

Therefore, FE = ED = 12 units.

Again, FD = FE + ED = 12 + 12 = 24 units. (Answer)

5 0
3 years ago
Use trigonometric substitution to verify that
photoshop1234 [79]
T = 0
=> Q = 0
 t = x
=> Q = arcsin(x/a)
 rest it just simple integration of trigonometric function
8 0
3 years ago
I need help this is so confusing
Gre4nikov [31]
Point c is quadrant 2,point T is quadrant 1,point R is x axis , point h is quadrant 3
5 0
2 years ago
Read 2 more answers
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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