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2 years ago

Pls answer question 8

Mathematics

1 answer:

iris [78.8K]2 years ago

6 0

Step-by-step explanation:

step 1: multiply $2^m$ by $3^n$

2 × 3 = 6

to times power you must add them

$2^m$ × $3^n$ = $6^{m+n}$

step 2: rearrange

$6^{m+n}$ = 108

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can you do this step by yourself

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3 years ago

Tim tiene 39 pares de audífonos y 13 reproductores de música. Tim quiere vender todos los audífonos y los reproductores de músic

Lena [83]

Answer: 13 packages.

Step-by-step explanation:

This can be translated to:

Tim has 39 pairs of headphones and 13 music players. Tim wants to sell all the headphones and music players in identical packages. What is the largest number of packages that Tim can do?

To solve this we must find the largest common factor between 39 and 13.

to do this, we divide the smaller number by different integers, and see if the result also divides the larger number into an integer.

13/1 =13 and 39/13 = 3

So 13 is the largest common factor.

This means that we can make 13 packages, each with:

39/13= 3 headphones

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4 years ago

Suppose you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. If you randomly

mina [271]

Answer:

(a) The probability you pass the exam is 0.0000501.

(b) The expected number of correct guesses is 7.5.

(c) The standard deviation is 2.372.

Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

$P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 30

r = number of success = at least 60%

p = probbaility of success which in our question is the probability

of a correct answer, i.e; p = $\frac{1}{4}$ = 0.25

Let X = Number of questions that are correct

So, X ~ Binom(n = 30 , p = 0.25)

(a) The probability you pass the exam is given by = P(X $\geq$ 18)

Because 60% of 30 = 18

P(X $\geq$ 18) = P(X = 18) + P(X = 19) +...........+ P(X = 29) + P(X = 30)

= $\binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}$