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Zepler [3.9K]
2 years ago
15

The sales department wants to place an order for 253,625 third grade math books for a region. Once the order is given, there is

always a need for extra math books. How can the sale manager estimate the number of math books to be sure that there are more then enough?
Mathematics
1 answer:
Vladimir [108]2 years ago
6 0

If the sales department wants to place an order for 253,625 third grade math books for a region. How can the sale manager estimate the number of math books to be sure that there are more then enough is: The manager should carryout survey based on the number of people per class and provide 25,362 books.

<h3></h3><h3>How the sale can manager estimate the number of math books </h3>

Since extra math's  books will be needed after giving out the available math's books.

Hence:

Additional maths books=10%× 253,625

Additional maths books=25,362 books

Based on the above calculation the manager should carryout survey based on the number of people per class and provide them with 25,362 books.

Therefore how can the sale manager estimate the number of math books to be sure that there are more then enough is that the manager should carryout survey based on the number of people per class and provide 25,362 books.

Learn more about How the sale can manager estimate the number of math books here:brainly.com/question/18558957

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According to Padgett Business Services, 20% of all small-business owners say the most important advice for starting a business i
elena-s [515]

Answer:

a) There is a 6.88% probability that none of the owners would say preparing for long hours and hard work is the most important advice.

b) There is a 1.93% probability that six or more owners would say preparing for long hours and hard work is the most important advice.

c) There is a 10.32% probability that exactly five owners would say having good financing ready is the most important advice.

d) The expected number of owners who would say having a good plan is the most important advice is 2.28

Step-by-step explanation:

Questions a), b), c) are all solved as binomial distribution problems.

Question d) is a simple calculation.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For these problems

12 business owners were contacted, so n = 12.

a. What is the probability that none of the owners would say preparing for long hours and hard work is the most important advice?

20% of all small-business owners say the most important advice for starting a business is to prepare for long hours and hard work, so \pi = 0.2.

That is P(X=0) when \pi = 0.2.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{12,0}.(0.2)^{0}.(0.8)^{12} = 0.0688

There is a 6.88% probability that none of the owners would say preparing for long hours and hard work is the most important advice.

b. What is the probability that six or more owners would say preparing for long hours and hard work is the most important advice?

20% of all small-business owners say the most important advice for starting a business is to prepare for long hours and hard work, so \pi = 0.2.

This is:

P = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 6) = C_{12,6}.(0.2)^{6}.(0.8)^{6} = 0.0155

P(X = 7) = C_{12,7}.(0.2)^{7}.(0.8)^{5} = 0.0033

P(X = 8) = C_{12,8}.(0.2)^{8}.(0.8)^{4} = 0.0005

P(X = 9) = C_{12,9}.(0.2)^{9}.(0.8)^{3} = 0.00006

P(X = 10) = C_{12,10}.(0.2)^{10}.(0.8)^{2} = 0.000004

P(X = 11) = C_{12,11}.(0.2)^{11}.(0.8)^{1} = 0.0000002

P(X = 12) = C_{12,12}.(0.2)^{12}.(0.8)^{0} = 0.000000004

So:

P = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.0155 + 0.0033 + 0.0005 + 0.000006 + 0.000004 + 0.0000002 + 0.000000004 = 0.0193

There is a 1.93% probability that six or more owners would say preparing for long hours and hard work is the most important advice.

c. What is the probability that exactly five owners would say having good financing ready is the most important advice?

Twenty-five percent say the most important advice is to have good financing ready, so \pi = 0.25

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 5) = C_{12,5}.(0.25)^{5}.(0.75)^{7} = 0.1032

There is a 10.32% probability that exactly five owners would say having good financing ready is the most important advice.

d. What is the expected number of owners who would say having a good plan is the most important advice?

Nineteen percent say having a good plan is the most important advice, so that is 0.19*12 = 2.28

The expected number of owners who would say having a good plan is the most important advice is 2.28

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3 years ago
Which values of a, b, and c represent the answer in simplest form?<br><br> 7/9 * 4/9 = a b/c
myrzilka [38]

Answer:

Option 2: A=1, B=3, C=4

Step-by-step explanation:

  1. 7/9÷4/9  = 7/9*9/4
  2. cancel 9 on each side
  3. =7/4
  4. = 1 3/4

4 0
2 years ago
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