Answer:
• For this one we need to split this problem into two equations:
• a (adults) + c (children) = 560
• 2a + c = $860
• Then we substitute 560 - a for c in the second equation.
- 2a + 560 - a = 860
- 2a + 560 = 860
- 2a = 530
- 2a = 265
• Then we plug this into the first equation:
Step-by-step explanation:
<h2>I hope this helps you !! </h2>
Consider the right triangle HBF. The Pythagorean theorem tells you ...
HF² = HB² + BF²
The lengths HB and BF can be determined by counting grid squares, or by subtracting coordinates. Here, it is fairly convenient to count grid squares. When we do that, we find ...
HB = 2
BF = 5
Using these values in the equation above, we get
HF² = 2² + 5²
HF² = 4 + 25 = 29
Taking the square root gives the length HF.
HF = √29
The area of a rectangle is obtained through the equation,
A = L x W
The width of the yard is 4 ft less than the length and may be expressed as L - 4. Length may be solved through the following steps,
A = (L)(L-4) ; 96 = L(L - 4) ; L = 12 ft
The length and width are 12 ft and 8 ft, respectively. Perimeter may be solved through the equation,
P = 2 x (L + W)
Substituting the values of L and W
P = 2 x ( 12 ft + 8 ft) = 40 ft
Therefore, the perimeter of the yard is 40 ft.
Is it 3g? idk sorry i need points