We have the following details
mean = 554
n = 60
bar x = 567
alpha = 0.01
<h3>How to solve for the hypothesis</h3>
A. h0. u = 554
H1. u > 554
B. Given that the standard deviation is known what we have to make use of is the independent z test
test statistics calculation
567-554/(39/√60)
= 2.582
d. at alpha = 0.01 and test statistics = 2.582, the value of the p value = 0.0049
0.0049 < 0.01. So we have to reject the null hypothesis.
e. Yes We have to accept that we support the preparation course's claim that the population mean SAT score of its graduates is greater than 554
Read more on statistics here:
brainly.com/question/19243813
#SPJ1