Answer:
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Explanation:
The answer is all of the above
Answer:
The correct option is: a. glycogen, starch, and amylopectin
Explanation:
Glycogen, amylopectin and starch are the polysaccharides of glucose. These polymers are composed of monomeric α-glucose units, which are joined by α(1→4) glycosidic bonds.
Since, the amylase enzyme can act only on the glycosidic bonds formed between α-glucose monomers. Therefore, amylase can break down glycogen, starch, and amylopectin.
Adenine, guanine, thymine and cytosine are the four nitrogenous bases that are attached to a sugar molecule<span> on each </span>side of the ladder<span>. When a phosphate, a sugar and a base form an attachment, they create a sub-unit of </span>DNA<span> called a nucleotide. Each nitrogenous base is held together by a hydrogen bond.</span>
Answer:
A.Glycogenesis: Glycogen synthase
B. Glucogenesis: Fructose 1,6 biphosphate phosphatase
C. Urea cycle : Carbamoyl phosphate synthetase
D.Fatty acid synthesis: Acetyl CoA carboxylase
E.Glycolysis : Phosphofructokinase 1
F. Pentose phosphate pathway: Glucose-6-phosphate dehydrogenase
Explanation:
A. Glycogen synthase converts glucose into glycogen during glycogenesis.
B. Fructose 1,6 biphosphate phosphatase catalyzes condensation of dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate during glucogenesis.
C. Carbamoyl phosphate synthetase I catalyses production of arbamoyl phosphate during urea cycle.
D. Carboxylase controls fatty acid metabolism.
E. The phosphofructokinase 1 is an important enzyme that regulate formation of two-phosphate sugar molecules during glycolysis.
F. Glucose-6-phosphate dehydrogenase participates in the pentose phosphate pathway. This pathway gives reducing energy to cells.
