Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
c. Resistant bacteria have survived and reproduced at a greater rate than nonresistant bacteria
Explanation:
The antibiotic is no longer effective as it was 20 years ago because the resistant bacterial have survived and reproduced at a greater rate than the non-resistant bacteria.
- The antibiotics have specifically designed to exterminate the disease causing bacteria strain from the body.
- While at that point in time, it is potent and does the work. Along the line, it will cause the structures of some other strains to change.
- This will lead to the development of resistant breeds with time.
- The resistant breed will then be able to survive the onslaught of the antibiotics making it not a good fit.
Learn more:
Selective force brainly.com/question/4602376
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Albedo is the "whiteness" of a surface. It is a reflection coefficient, and has a value of less than one. The albedo of a surface is the ratio of radiation reflected from the surface to the incident radiation. Hope this helps. Have a nice day. Feel free to ask more questions.
