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3 years ago

7

53, 64, 19, 25, 88, 48, 46Mean:Mode:Median:Range:

1 answer:

levacccp [35]3 years ago

7 0

Answer:

Mean: 49

Mode: none, since all the numbers only appear once

Median: 48

Range: 69

Step-by-step explanation:

53+64+19+25+88+48+46 = 343

343/7= 49 (mean)

19, 25, 26, 48, 53, 64, 88 (middle number is 48, so the median is 48)

Range= largest number-smallest number

88-19= 69 (range)

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Answer:

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Step-by-step explanation:

I am going to call B1 the balance for the first deposit, B2 the balance for the second deposit and B3 for the third deposit.

This is a compound interest problem.

The compound interest formula is given by:

$A = P(1 + \frac{r}{n})^{nt}$

A: Amount of money(Balance)

P: Principal(Initial deposit)

r: interest rate(as a decimal value)

n: number of times that interest is compounded per unit t

t: time the money is invested or borrowed for.

First step: Balance B1 on December 1, 2016

A = amount of money = B1

P = 1,700

r = 0.056

n = 12(compounded mothly, and t is in years)

t = 8 years

$B1 = 1700(1 + \frac{0.056}{12})^{96}$

$B1 = $2658.17$

Second step: Balance B2 on December 1, 2016

A = B3

P = 1,700

r = 0.056

n = 12(compounded mothly, and t is in years)

t: From January 1, 2010 to December 1, 2016 there are 6 years and 11 months. 11 months is 0.92 of a year. So

t = 6.92

$B2 = 1700(1 + \frac{0.056}{12})^{83.04}$

$B2 = $2502.39$

Third step: Balance B3 on December 1, 2016

A = B3

P = 1700

r = 0.056

n = 12

t: 4 years and 7 months. 7 months is 7/12 = 0.58. So t = 4.58 years.

$B3 = 1700(1 + \frac{0.056}{12})^{54.96}$

$B3 = $2195.72$

Final step: Total balance on December 1, 2016

B = 2195.72 + 2502.39 + 2658.17

B = $7356.28

So the total balance on December 1, 2016 is B = $7356.28

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