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tresset_1 [31]
3 years ago
7

53, 64, 19, 25, 88, 48, 46Mean:Mode:Median:Range:​

Mathematics
1 answer:
levacccp [35]3 years ago
7 0

Answer:

Mean: 49

Mode: none, since all the numbers only appear once

Median: 48

Range: 69

Step-by-step explanation:

53+64+19+25+88+48+46 = 343

343/7= 49 (mean)

19, 25, 26, 48, 53, 64, 88 (middle number is 48, so the median is 48)

Range= largest number-smallest number

88-19= 69 (range)

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The triangles are similar. <br> What is the value of x?<br> Enter your answer in the box.
Ipatiy [6.2K]

Answer:

\boxed{\boxed{x=4}}

Step-by-step explanation:

If the triangles are similar, then the sides are in proportion.

We have the equation:

\dfrac{3x+8}{4}=\dfrac{15}{3}             <em>cross multiply</em>

3(3x+8)=(4)(15)          <em>divide both sides by 3</em>

3x+8=(4)(5)

3x+8=20           <em>subtract 8 from both sides</em>

3x=12           <em>divide both sides by 3</em>

\boxed{x=4}

5 0
4 years ago
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Determine a series of transformations that would map Figure S onto Figure T.
olga_2 [115]

Answer: 5.4

Step-by-step explanation:

4 0
3 years ago
1) Carefully follow the steps to find the solution to the three equation system.
rjkz [21]

Step-by-step explanation:

a. we simply subtract 3. from 2.

x + 2y + z = 15

- -3x + y + z = 2

--------------------------

4x + y 0 = 13

b. we multiply 3. by 3 and then subtract from 1.

2x - 4y + 3z = -7

- -9x + 3y + 3z = 6

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11x - 7y 0 = -13

c. we multiply the result of a. by 7, and then simply add a. and b., because the y terms have different signs already.

28x + 7y = 91

+ 11x - 7y = -13

--------------------------

39x 0 = 78

39x = 78

x = 2

d. we use this x = 2 in the result of a.

4×2 + y = 13

8 + y = 13

y = 5

e. using x = 2 and y = 5 in 2.

2 + 2×5 + z = 15

2 + 10 + z = 15

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the solution is therefore (2, 5, 3).

8 0
1 year ago
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Jenna spends $15.04 at the store on notebooks and folders for school. Notebooks cost $4.85 each, and folders cost $0.89 each. Sh
cluponka [151]

Answer:

\boxed{\text{2 notebooks and 6 folders}}

Step-by-step explanation:

Let n = number of notebooks

and f = number of fodders

You have a system of two equations:

\begin{cases}(1)& 4.85n + 0.89f = 15.04\\(2) & n+ f = 8\end{cases}\\\\

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Jenna bought \boxed{\textbf{two notebooks and six folders} }.

Check:

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OK.

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Pachacha [2.7K]

Answer:

The answer is A/ 5 and 3 thirds

Step-by-step explanation:

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